Rates of Reaction Notes
AQA GCSE Chemistry: Revision notes
Key facts
- Rate = quantity of reactant used (or product formed) ÷ time, in units such as g/s or cm³/s.
- A steeper gradient on a graph of product against time means a faster rate.
- Higher concentration, surface area and temperature, or a catalyst, increase the rate.
- Collision theory: reactions happen when particles collide with enough energy; faster reactions have more frequent or more energetic collisions.
- Catalysts lower the activation energy and are not used up.
Calculating rate
Rate is the quantity of reactant used up or product formed divided by the time taken.
The quantity can be mass (g), gas volume (cm³) or concentration (mol/dm³). The rate of reaction has units such as g/s, cm³/s or mol/(dm³·s).
A faster reaction has a larger rate value.
- Rate
Worked example
A reaction produces 8 g of product in 40 seconds. Another produces 12 g in 60 seconds. Compare their rates.
- 1
Reaction 1: rate = 8 ÷ 40 = 0.2 g/s.
- 2
Reaction 2: rate = 12 ÷ 60 = 0.2 g/s.
A reaction makes 30 cm³ of gas in 20 s. What is the rate?
Measuring rate
Track mass lost, gas volume made, or the time for a precipitate to hide a cross.
Choose the method to suit the reaction. In the cross experiment a precipitate forms in a beaker over a cross on paper. Time how long until the cross can no longer be seen from above.
| Measures | Example | |
|---|---|---|
| Change in mass | Mass lost as gas | Calcium carbonate with acid |
| Gas collected | Volume of gas made | Metal with dilute acid |
| Precipitate (cross) | Time for cross to disappear | Sodium thiosulfate with acid |
Measures
- Change in mass:
- Mass lost as gas
- Gas collected:
- Volume of gas made
- Precipitate (cross):
- Time for cross to disappear
Example
- Change in mass:
- Calcium carbonate with acid
- Gas collected:
- Metal with dilute acid
- Precipitate (cross):
- Sodium thiosulfate with acid
- 1
Draw a cross
on paper beneath a beaker
- 2
Start the timer
as the reaction begins
- 3
Watch from above
the precipitate hides the cross
- 4
Record the time
when the cross cannot be seen
Which method suits a reaction that forms an insoluble product?
Rate graphs
On a graph of product against time, steepness shows rate: steep at the start, flat when finished.
A steeper gradient means a faster rate. The gradient falls over time as reactants are used up, and the line goes flat when the reaction stops.
Do not confuse a concentration-time graph (amount remaining) with how fast the reaction is going at each moment.
Where is the rate fastest on this type of graph?
Concentration
More particles in the same volume collide more often, so the rate rises.
Collision theory: a reaction needs particles to collide with enough energy. Increasing concentration puts more particles in the same volume, so collisions are more frequent.
The activation energy does not change. A higher starting concentration gives a steeper curve at the start and the reaction finishes sooner.
Low concentration
High concentration
Why does a higher concentration increase the rate?
Temperature and surface area
Heating makes collisions more frequent and more energetic; a larger surface area exposes more solid.
Temperature: particles move faster, so collisions are more frequent. More particles also have at least the activation energy, which is the more important effect.
Surface area: breaking a solid into smaller pieces exposes more of it to collide with. Marble powder reacts faster than marble chips.
Why does powdered marble react faster than marble chips?
Catalysts and tangents (HT)
A catalyst lowers the activation energy; a tangent gives the rate at one point on a curve.
A catalyst speeds up a reaction without being used up by lowering the activation energy. More particles can then react at the same temperature.
(HT) On a curved concentration-time graph, draw a tangent at the point and calculate its gradient: change in concentration ÷ change in time.
- 1
Pick the point
on the curve
- 2
Draw a tangent
touches the curve without crossing
- 3
Find the gradient
(y₂ − y₁) ÷ (t₂ − t₁)
- 4
Interpret
gradient = rate at that moment
Worked example
At 10 s the concentration is 0.8 mol/dm³. A tangent there passes through 8 s (0.9 mol/dm³) and 12 s (0.7 mol/dm³). Find the rate at 10 s.
- 1
Gradient = (0.7 − 0.9) ÷ (12 − 8).
- 2
= −0.2 ÷ 4 = −0.05 mol/(dm³·s).
- 3
The negative sign shows concentration is falling.
What does a steeper tangent on a concentration-time graph show?
Try an exam question
Marble chips react with dilute hydrochloric acid. Explain, using collision theory, why powdered marble reacts faster than the same mass of marble chips.
[3 marks]
- [1]Powder has a larger surface area.
- [1]So more particles of marble are exposed to the acid.
- [1]There are more frequent collisions between particles, so the rate increases.
That's the notes covered.
Carry on to the next subtopic.