Oxidation, reduction and redox equationsAQA A-Level Chemistry: Topic test
20 questions, 54 marks
AQA A-Level Chemistry
Oxidation, reduction and redox equations topic test
Total 54 marks
Name
Class
Date
- 1Magnesium ribbon continues to burn when it is lowered into a gas jar of carbon dioxide, forming white magnesium oxide and black specks of carbon: 2Mg(s) + CO₂(g) → 2MgO(s) + C(s).(a)Which species is the reducing agent in this reaction?[1 mark]
- AMg
- BCO₂
- CC
- DMgO
(b)What is the change in the oxidation state of carbon?[1 mark]- A−4 to 0
- B+2 to 0
- C+4 to 0
- D+4 to −4
(c)Write half-equations for the oxidation process and for the reduction process in this reaction.[2 marks]Total for question 1: 4 marks
- 2Chlorine gas is bubbled into cold, dilute aqueous sodium hydroxide to make household bleach: Cl₂(g) + 2NaOH(aq) → NaCl(aq) + NaClO(aq) + H₂O(l).(a)What is the oxidation state of chlorine in sodium chlorate(I), NaClO?[1 mark]
- A−1
- B+1
- C+3
- D+5
(b)Which statement about the chlorine in this reaction is correct?[1 mark]- AIt is oxidised only
- BIt is reduced only
- CIts oxidation state does not change
- DIt is both oxidised and reduced
(c)Write the half-equation for the reduction of chlorine in this reaction, and state the change in oxidation state of the chlorine that is oxidised.[2 marks]Total for question 2: 4 marks
- 3Copper reacts with dilute nitric acid to form blue copper(II) nitrate solution and nitrogen monoxide gas, which turns brown in air. The overall equation is 3Cu(s) + 8H⁺(aq) + 2NO₃⁻(aq) → 3Cu²⁺(aq) + 2NO(g) + 4H₂O(l).(a)Write half-equations for the oxidation of copper and for the reduction of nitrate ions to nitrogen monoxide in acidic solution, and name the oxidising agent.[3 marks](b)Use oxidation states to show that the overall equation is balanced for electron transfer.[4 marks]
Total for question 3: 7 marks
- 4Sulfur dioxide takes part in two redox reactions. In the first, it decolourises acidified potassium manganate(VII) solution, forming sulfate ions, SO₄²⁻, and manganese(II) ions, Mn²⁺. In the second, it reacts with hydrogen sulfide gas to form solid sulfur and water: SO₂(g) + 2H₂S(g) → 3S(s) + 2H₂O(l).(a)For the reaction with acidified manganate(VII) ions, give the oxidation states that change, write both half-equations, and combine them to give the overall ionic equation.[6 marks](b)In the second reaction, sulfur dioxide acts as an oxidising agent, whereas in the first reaction it acts as a reducing agent. Use oxidation states and half-equations to explain this, and show how the half-equations combine to give the equation for the second reaction.[6 marks]
Total for question 4: 12 marks
- 5Acidified potassium manganate(VII) oxidises ethanedioate ions, C₂O₄²⁻, to carbon dioxide when the mixture is warmed. The manganate(VII) ions are reduced to manganese(II) ions.(a)What is the oxidation state of carbon in the ethanedioate ion, C₂O₄²⁻?[1 mark]
- A+2
- B+4
- C+3
- D−3
(b)Which is the correct half-equation for the oxidation of ethanedioate ions to carbon dioxide?[1 mark]- AC₂O₄²⁻ → 2CO₂ + 2e⁻
- BC₂O₄²⁻ + 2e⁻ → 2CO₂
- CC₂O₄²⁻ → 2CO₂ + e⁻
- DC₂O₄²⁻ → CO₂ + 2e⁻
(c)The half-equation for the reduction is MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O. Combine this with the oxidation half-equation to give the overall ionic equation.[2 marks]Total for question 5: 4 marks
- 6In the thermite reaction, powdered aluminium reacts with iron(III) oxide at a very high temperature, producing molten iron: Fe₂O₃(s) + 2Al(s) → Al₂O₃(s) + 2Fe(l). The reaction is used to weld railway lines.(a)Which statement identifies the reducing agent and gives the reason?[1 mark]
- AFe₂O₃, because the oxidation state of iron falls
- BAl₂O₃, because it is the oxide that is formed
- CFe, because it is the product of the reaction
- DAl, because its oxidation state rises
(b)How many moles of electrons are transferred when one mole of Fe₂O₃ reacts?[1 mark]- A3
- B6
- C2
- D12
(c)Write the half-equation for the oxidation of aluminium and the half-equation for the reduction of iron(III) ions to iron in this reaction.[2 marks]Total for question 6: 4 marks
- 7Iodate(V) ions oxidise iodide ions in acidic solution, forming iodine: IO₃⁻(aq) + 5I⁻(aq) + 6H⁺(aq) → 3I₂(aq) + 3H₂O(l).(a)State the oxidation state of iodine in IO₃⁻, in I⁻ and in I₂, and identify the oxidising agent and the reducing agent.[3 marks](b)Write half-equations for the formation of iodine from iodate(V) ions and from iodide ions, and show how they combine to give the equation in the question.[4 marks]
Total for question 7: 7 marks
- 8Two redox reactions are studied. In the first, copper(I) oxide dissolves in dilute sulfuric acid, giving copper metal and a blue solution of copper(II) ions: Cu₂O(s) + 2H⁺(aq) → Cu(s) + Cu²⁺(aq) + H₂O(l). In the second, ammonia is burned in oxygen over a platinum catalyst in the manufacture of nitric acid: 4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(g).(a)Use oxidation states to explain why the first reaction is a redox reaction of a particular type, and say what happens to the oxidation states of oxygen and hydrogen. Show how the copper half-equations combine.[6 marks](b)For the second reaction, use oxidation states to identify the oxidising agent and reducing agent, and use half-equations in acidic form to show how the overall equation arises.[6 marks]
Total for question 8: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).