AlkenesEdexcel International A Level Chemistry: Topic test
20 questions, 54 marks
Edexcel International A Level Chemistry
Alkenes topic test
Total 54 marks
Name
Class
Date
- 1A chemist is given four alkenes, each with the molecular formula C₆H₁₂: hex-1-ene, 2-methylpent-2-ene, 3-methylpent-2-ene and 2,3-dimethylbut-2-ene.(a)Which of these alkenes shows E-Z (geometric) isomerism?[1 mark]
- A3-methylpent-2-ene
- B2-methylpent-2-ene
- Chex-1-ene
- D2,3-dimethylbut-2-ene
(b)Which statement about the C=C double bond in these alkenes is correct?[1 mark]- AIt consists of two σ bonds, each formed by head-on overlap of orbitals
- BIt consists of a σ bond formed by sideways overlap and a π bond formed by head-on overlap
- CIt consists of a σ bond formed by head-on overlap of orbitals and a π bond formed by sideways overlap of p orbitals
- DIt consists of a σ bond and a π bond, with the π electron density lying along the line joining the two carbon nuclei
(c)In one isomer of 3-methylpent-2-ene the CH₃ group on carbon 2 and the CH₂CH₃ group on carbon 3 lie on the same side of the double bond. State whether this is the E or the Z isomer and justify your answer using the priorities of the groups.[2 marks]Total for question 1: 4 marks
- 2A chemist reacts but-1-ene, CH₃CH₂CH=CH₂, with a range of reagents in separate experiments.(a)What is the organic product when but-1-ene is shaken with cold, dilute, acidified potassium manganate(VII) solution?[1 mark]
- Abutan-2-ol
- Bbutane
- C1,2-dibromobutane
- Dbutane-1,2-diol
(b)Which observation is made when but-1-ene is shaken with bromine water?[1 mark]- AThe solution stays orange
- BThe orange solution becomes colourless
- CThe colourless solution turns orange
- DA white precipitate forms
(c)But-1-ene reacts with steam in the presence of a phosphoric acid catalyst to form two isomeric alcohols. Name the major product and explain why it is formed in the greater amount.[2 marks]Total for question 2: 4 marks
- 3A chemist converts 5.60 g of but-1-ene, C₄H₈, into 2-bromobutane by reacting it with hydrogen bromide. Relative atomic masses: H = 1.0, C = 12.0, Br = 80.0.(a)The chemist obtains 9.59 g of 2-bromobutane. Calculate the percentage yield.[3 marks](b)Describe the mechanism of the reaction of but-1-ene with hydrogen bromide, stating where each curly arrow starts and finishes, and explain why 2-bromobutane is the major product.[4 marks]
Total for question 3: 7 marks
- 4Pent-2-ene, CH₃CH=CHCH₂CH₃, exists as two geometric isomers and reacts with bromine in an inert solvent.(a)Explain, with reference to the bonding in the C=C bond, why pent-2-ene exists as two geometric isomers, and use the E-Z system to name the isomer in which the CH₃ and CH₂CH₃ groups lie on opposite sides of the double bond.[6 marks](b)Describe, in words, the mechanism of the reaction of pent-2-ene with bromine, stating where each curly arrow starts and finishes, and name the product.[6 marks]
Total for question 4: 12 marks
- 5Poly(phenylethene), commonly called polystyrene, is used for disposable cups and packaging. Its monomer is phenylethene, C₆H₅CH=CH₂.(a)Which is the repeat unit of poly(phenylethene)?[1 mark]
- A–CH(C₆H₅)–CH(C₆H₅)–
- B–CH₂–CH₂–C₆H₅–
- C–CH₂–CH(C₆H₅)–
- D–CH₂–C(C₆H₅)₂–
(b)Which statement about the formation of poly(phenylethene) is correct?[1 mark]- AIt forms with no other product, so every atom in the monomer appears in the polymer
- BIt forms by loss of a small molecule such as water between monomers
- CThe polymer contains C=C bonds and so decolourises bromine water
- DEach monomer loses a hydrogen atom as the chain forms
(c)A sample of poly(phenylethene) has an average relative molecular mass of 52 000. Calculate the average number of repeat units in each chain. Relative atomic masses: H = 1.0, C = 12.0.[2 marks]Total for question 5: 4 marks
- 62-Methylbut-2-ene, (CH₃)₂C=CHCH₃, reacts with hydrogen bromide to form two isomeric bromoalkanes by an electrophilic addition mechanism.(a)Which is the major product of this reaction?[1 mark]
- A2-bromo-3-methylbutane
- B1-bromo-2-methylbutane
- C2,3-dibromo-2-methylbutane
- D2-bromo-2-methylbutane
(b)Which statement best explains why the intermediate leading to the major product is more stable than the one leading to the minor product?[1 mark]- AIt has fewer alkyl groups, so the positive charge is concentrated on one carbon
- BIts three alkyl groups release electron density towards the positively charged carbon
- CThe positively charged carbon carries more hydrogen atoms
- DThe positively charged carbon has a full outer shell of eight electrons
(c)Name the minor product of this reaction and explain why it is formed in a smaller amount.[2 marks]Total for question 6: 4 marks
- 7A manufacturer makes hot-water pipes from poly(but-1-ene) and drain pipes from poly(chloroethene), PVC. Relative atomic masses: H = 1.0, C = 12.0.(a)Give the repeat unit of poly(but-1-ene) and calculate the relative molecular mass of a chain that contains 2000 repeat units.[3 marks](b)Offcuts of PVC are sometimes burned. Explain why the waste gases must be treated, how this is done, and why chemists are developing biodegradable polymers as an alternative to disposal.[4 marks]
Total for question 7: 7 marks
- 8A chemist compares the reactions of hex-3-ene, CH₃CH₂CH=CHCH₂CH₃, and hex-2-ene, CH₃CH=CHCH₂CH₂CH₃.(a)Each alkene reacts with hydrogen bromide. Explain, with reference to carbocation intermediates, why hex-3-ene forms only one product whereas hex-2-ene forms a mixture of two, and name the products.[6 marks](b)Explain why hex-3-ene shows geometric isomerism and name the isomer in which the two ethyl groups lie on the same side of the double bond. State the organic product when hex-3-ene reacts separately with (i) hydrogen and a nickel catalyst and (ii) cold, dilute, acidified potassium manganate(VII), and give the colour change seen in (ii).[6 marks]
Total for question 8: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).