Energetics IEdexcel A-Level Chemistry: Topic test
20 questions, 54 marks
Edexcel A-Level Chemistry
Energetics I topic test
Total 54 marks
Name
Class
Date
- 1Magnesium burns in oxygen with a bright white flame: 2Mg(s) + O₂(g) → 2MgO(s). Under standard conditions the enthalpy change for the equation as written is −1204 kJ.(a)What is the standard enthalpy change of formation of magnesium oxide, in kJ mol⁻¹?[1 mark]
- A−1204
- B−602
- C+602
- D−301
(b)Which set of conditions is used for a standard enthalpy change?[1 mark]- AA pressure of 100 kPa and a stated temperature, usually 298 K
- BA pressure of 100 kPa and a temperature of exactly 273 K
- CA concentration of 1 mol dm⁻³ for every substance, at 298 K
- DAny pressure, provided that the temperature is 298 K
(c)Define the term standard enthalpy change of formation.[2 marks]Total for question 1: 4 marks
- 24.00 g of solid ammonium nitrate, NH₄NO₃ (molar mass 80.0 g mol⁻¹), is dissolved in 50.0 cm³ of water in an insulated polystyrene cup. The temperature falls from 21.0 °C to 14.6 °C. Treat the mass of solution as 50.0 g, and assume the specific heat capacity of the solution is 4.18 J g⁻¹ K⁻¹.(a)What is the enthalpy change for the dissolving of ammonium nitrate, in kJ per mole of ammonium nitrate?[1 mark]
- A−26.8
- B+1.34
- C+26.8
- D+26 800
(b)Which statement describes the enthalpy level diagram for this change?[1 mark]- AThe products are at a lower enthalpy than the reactants, and ΔH is negative
- BThe products are at the same enthalpy as the reactants, and ΔH is zero
- CThe reactants are at a higher enthalpy than the products, because the temperature has fallen
- DThe products are at a higher enthalpy than the reactants, and ΔH is positive
(c)The true enthalpy change is more endothermic than the value found. Suggest an experimental reason, and explain its effect.[2 marks]Total for question 2: 4 marks
- 3Standard enthalpy changes of combustion at 298 K: carbon (graphite) −394 kJ mol⁻¹, hydrogen −286 kJ mol⁻¹, propene, C₃H₆(g), −2058 kJ mol⁻¹, propane, C₃H₈(g), −2219 kJ mol⁻¹.(a)Use Hess's law to calculate the standard enthalpy change for the hydrogenation of propene, C₃H₆(g) + H₂(g) → C₃H₈(g).[3 marks](b)Calculate the standard enthalpy change of formation of propene, 3C(s) + 3H₂(g) → C₃H₆(g).[4 marks]
Total for question 3: 7 marks
- 4Anhydrous copper(II) sulfate reacts with water to form the hydrate: CuSO₄(s) + 5H₂O(l) → CuSO₄·5H₂O(s). This enthalpy change cannot be measured directly, so a student uses Hess's law. In experiment 1, 2.00 g of anhydrous CuSO₄ (molar mass 159.6 g mol⁻¹) is added to 25.0 cm³ of water and the temperature rises by 8.0 K. In experiment 2, 3.13 g of CuSO₄·5H₂O (molar mass 249.6 g mol⁻¹) is added to 25.0 cm³ of water and the temperature falls by 1.4 K. In both experiments treat the mass of solution as 25.0 g with a specific heat capacity of 4.18 J g⁻¹ K⁻¹. The thermometer reads to ±0.1 °C.(a)Calculate the enthalpy change of solution for each solid, in kJ mol⁻¹, and use them to calculate the enthalpy change for CuSO₄(s) + 5H₂O(l) → CuSO₄·5H₂O(s).[6 marks](b)Evaluate the method: explain why Hess's law is needed, calculate the percentage uncertainty in the temperature change in each experiment, and suggest one improvement to the procedure.[6 marks]
Total for question 4: 12 marks
- 5Hydrazine, N₂H₄, is used as a rocket fuel: N₂H₄(g) + O₂(g) → N₂(g) + 2H₂O(g). Mean bond enthalpies in kJ mol⁻¹: N–N 158, N–H 391, O=O 498, N≡N 945, O–H 464. The enthalpy change for this reaction calculated from standard enthalpies of formation, with all species gaseous, is −543 kJ mol⁻¹.(a)What is the enthalpy change for the reaction calculated from the mean bond enthalpies?[1 mark]
- A−581 kJ mol⁻¹
- B+581 kJ mol⁻¹
- C−2145 kJ mol⁻¹
- D−2801 kJ mol⁻¹
(b)Why does the answer from mean bond enthalpies differ from −543 kJ mol⁻¹?[1 mark]- ABond breaking is exothermic, so the signs in the bond enthalpy calculation are unreliable.
- BHess's law does not apply to reactions that involve gases.
- CMean bond enthalpies are measured at 0 K, but formation data are measured at 298 K.
- DMean bond enthalpies are averages taken over many compounds, so they are not exact for the bonds in these molecules.
(c)State what is meant by the term mean bond enthalpy.[2 marks]Total for question 5: 4 marks
- 6A student burns 1.48 g of butan-1-ol (molar mass 74.0 g mol⁻¹) in a spirit burner under a metal can containing 250 g of water. The temperature of the water rises by 19.0 K. The specific heat capacity of water is 4.18 J g⁻¹ K⁻¹. The data book value for the standard enthalpy change of combustion of butan-1-ol is −2676 kJ mol⁻¹.(a)What is the experimental enthalpy change of combustion of butan-1-ol, in kJ mol⁻¹?[1 mark]
- A+993
- B−19.9
- C−993
- D−993 000
(b)Which is the main reason the experimental value is much less exothermic than the data book value?[1 mark]- AThe specific heat capacity of water increases as it is heated.
- BMuch of the energy is lost to the surroundings and the can, and combustion may be incomplete.
- CThe data book value applies only to solutions, not to liquids.
- DThe mass of water used is too large for the sample of alcohol.
(c)Suggest two changes to the apparatus that would give a value closer to the data book value.[2 marks]Total for question 6: 4 marks
- 7Hydrogen peroxide decomposes in the presence of a catalyst: 2H₂O₂(l) → 2H₂O(l) + O₂(g). Standard enthalpy changes of formation: H₂O₂(l) −188 kJ mol⁻¹, H₂O(l) −286 kJ mol⁻¹.(a)Calculate the standard enthalpy change for the reaction as written.[3 marks](b)1.00 mol of hydrogen peroxide decomposes in 500 g of aqueous solution. Calculate the maximum temperature rise, assuming the specific heat capacity of the solution is 4.18 J g⁻¹ K⁻¹, and state one reason why the actual rise is smaller.[4 marks]
Total for question 7: 7 marks
- 8Ethyne is hydrogenated to ethane in the presence of a nickel catalyst: C₂H₂(g) + 2H₂(g) → C₂H₆(g). Mean bond enthalpies in kJ mol⁻¹: C≡C 839, C–C 347, C–H 413, H–H 436. Standard enthalpies of formation in kJ mol⁻¹: C₂H₂(g) +227, C₂H₆(g) −84.(a)Calculate the enthalpy change for the reaction using the mean bond enthalpies, and again using the enthalpies of formation. Comment on the difference between the two values.[6 marks](b)Explain, in terms of bonds, why the reaction is exothermic. Describe the enthalpy level diagram for the reaction and state the standard conditions for the enthalpy change.[6 marks]
Total for question 8: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).