Nuclear radiationEdexcel A-Level Physics: Topic test
20 questions, 54 marks
Edexcel A-Level Physics
Nuclear radiation topic test
Total 54 marks
Name
Class
Date
- 1Radon-222 (proton number 86) is a radioactive gas that seeps out of some rocks into buildings. It decays by alpha emission. A later nuclide in its decay chain, bismuth-214 (proton number 83), decays by beta-minus emission to polonium (proton number 84).(a)Which nuclide is formed when a nucleus of radon-222 emits an alpha particle?[1 mark]
- A
- B
- C
- D
(b)Which statement best explains why radon gas is a health hazard when it is breathed in, even though alpha particles cannot penetrate the skin?[1 mark]- AAlpha particles are weakly ionising but they penetrate deep into the body
- BAlpha particles are the most penetrating radiation and pass through the chest wall
- CRadon is a gamma emitter, so its radiation passes through the body
- DAlpha particles are strongly ionising and are absorbed in a short distance, so inside the lungs all their energy is delivered to nearby cells
(c)Write a nuclear equation for the decay of bismuth-214 by beta-minus emission.[2 marks]Total for question 1: 4 marks
- 2A sealed source of unknown type is tested with a detector at a fixed distance. The background radiation gives 24 counts per minute. The count rates recorded, in counts per minute, are: no absorber 840; with a sheet of paper 838; with 3.0 mm of aluminium 26.(a)What is the corrected count rate with no absorber?[1 mark]
- A864 counts per minute
- B840 counts per minute
- C816 counts per minute
- D838 counts per minute
(b)Which type of radiation does the source emit?[1 mark]- ABeta only
- BAlpha only
- CGamma only
- DAlpha and gamma
(c)Calculate the percentage of the corrected count rate that is removed by the 3.0 mm of aluminium.[2 marks]Total for question 2: 4 marks
- 3Data for a lithium-7 nucleus, which contains 3 protons and 4 neutrons: nuclear mass = 7.014358 u. Mass of a proton = 1.007276 u. Mass of a neutron = 1.008665 u. 1 u = 1.66 × 10⁻²⁷ kg. Speed of light, c = 3.00 × 10⁸ m s⁻¹. Elementary charge, e = 1.60 × 10⁻¹⁹ C.(a)Calculate the mass deficit of the lithium-7 nucleus in kg.[3 marks](b)Calculate the binding energy of the lithium-7 nucleus in MeV and its binding energy per nucleon. State what the binding energy per nucleon shows.[4 marks]
Total for question 3: 7 marks
- 4Binding energy per nucleon values, in MeV: uranium-235 7.6; barium-141 8.3; krypton-92 8.5; iron-56 8.8. Iron-56 lies at the maximum of the binding energy per nucleon curve. Elementary charge, e = 1.60 × 10⁻¹⁹ C.(a)In the core of a massive star, nuclei lighter than iron-56 fuse together. Explain why fusion of lighter nuclei releases energy but fusion of iron-56 nuclei does not, and why fusion requires very high temperature and density.[6 marks](b)One fission reaction is . Calculate the energy released in one fission in MeV and in J. A reactor has a thermal power of 1.2 GW; calculate the number of fissions per second. Explain why energy is released in this fission.[6 marks]
Total for question 4: 12 marks
- 5Carbon-14 has a half-life of 5730 years. A 1.00 g sample of carbon from living wood has an activity of 0.230 Bq. A 1.00 g sample of carbon from a wooden artefact found at a dig has an activity of 0.0575 Bq. Take 1 year = 3.156 × 10⁷ s.(a)What is the decay constant of carbon-14?[1 mark]
- A3.83 × 10⁻¹² s⁻¹
- B1.21 × 10⁻⁴ s⁻¹
- C5.53 × 10⁻¹² s⁻¹
- D1.92 × 10⁻¹² s⁻¹
(b)What is the age of the artefact?[1 mark]- A5 700 years
- B17 200 years
- C11 500 years
- D23 000 years
(c)Calculate the number of carbon-14 nuclei in the sample from the artefact.[2 marks]Total for question 5: 4 marks
- 6A radioactive isotope is prepared in a laboratory. Its initial activity is 2.56 × 10⁴ Bq. Forty-eight minutes later the activity has fallen to 1.60 × 10³ Bq. Background radiation may be ignored.(a)What is the half-life of the isotope?[1 mark]
- A48 min
- B24 min
- C16 min
- D12 min
(b)What activity is expected a further 36 minutes later?[1 mark]- A4.0 × 10² Bq
- B2.0 × 10² Bq
- C5.3 × 10² Bq
- D0 Bq
(c)A student says: "The half-life is 12 minutes, so after 24 minutes the whole sample will have decayed." Explain why this statement is wrong.[2 marks]Total for question 6: 4 marks
- 7A thickness gauge in a factory contains a sealed source of strontium-90, which has a half-life of 28.8 years. The initial activity of the source is 3.7 × 10⁶ Bq. Take 1 year = 3.156 × 10⁷ s.(a)Calculate the decay constant of strontium-90 in s⁻¹.[3 marks](b)Calculate the number of strontium-90 nuclei in the source at the start and the activity of the source after 10 years.[4 marks]
Total for question 7: 7 marks
- 8Iridium-192 is a beta-minus and gamma emitter with a half-life of 74 days. Small sealed wires of iridium-192 are placed temporarily inside tumours to treat cancer. One wire has an initial activity of 1.2 × 10⁹ Bq.(a)Evaluate the suitability of iridium-192 for this use, referring to the types of radiation it emits and to its half-life. Compare it with an alpha emitter and with a source of half-life 5 minutes.[6 marks](b)The wire is to be stored until its activity has fallen to 5.0% of its initial value. Calculate the activity at which it can be disposed of and the time this takes. Explain why the activity measured with a detector must be corrected for background radiation.[6 marks]
Total for question 8: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).