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Mensuration and CalculationAQA GCSE Maths: Revision notes

Section 1

How Do We Calculate Area and Perimeter of 2D Shapes?

You must know and apply formulae to calculate the areas of:

  • Triangle: Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
  • Parallelogram: Area=base×height\text{Area} = \text{base} \times \text{height}
  • Trapezium: Area=12(a+b)h\text{Area} = \frac{1}{2}(a+b)h, where aa and bb are the parallel sides

Perimeter is the total distance around the outside of a shape — add all the side lengths together. Standard units of measure (length, area, volume/capacity, mass, time, money) must be used and applied correctly, including in geometrical problems set on coordinate axes.

Key termsareaperimetertrapezium
Example

A trapezium with parallel sides 6 cm and 10 cm and height 4 cm has area 12(6+10)(4)=32 cm2\frac{1}{2}(6+10)(4) = 32\text{ cm}^2.

Section 2

How Do We Calculate the Circumference and Area of a Circle?

Know the formulae:

  • Circumference: C=2πr=πdC = 2\pi r = \pi d
  • Area: A=πr2A = \pi r^2

These can be used to find the perimeter of composite 2D shapes involving circles, and the area of circles and composite shapes (shapes made of more than one basic shape). Answers may be required in terms of π\pi (i.e. left with π\pi in the answer rather than as a decimal).

Key termscircumferencecomposite shape
Exam tip

If a question says 'give your answer in terms of π\pi', do not convert π\pi to a decimal — leave it as a symbol in the final answer.

Section 3

How Do We Calculate Arc Length and Sector Area?

A sector is a 'slice' of a circle between two radii, and an arc is the curved part of its boundary. Given the angle θ\theta at the centre:

  • Arc length =θ360×2πr= \frac{\theta}{360} \times 2\pi r
  • Sector area =θ360×πr2= \frac{\theta}{360} \times \pi r^2

At Higher tier, this extends to frustums — a cone or pyramid with the top cut off parallel to the base.

Key termssectorarcfrustum
Example

A sector with radius 6 cm and angle 90° has area 90360×π×62=9π cm2\frac{90}{360} \times \pi \times 6^2 = 9\pi \text{ cm}^2.

Section 4

How Do We Calculate Volume and Surface Area of 3D Shapes?

You must be able to calculate:

  • Volumes of cuboids and other right prisms, including cylinders — volume of a prism == cross-sectional area ×\times length
  • Surface area and volume of spheres, pyramids and cones, and composite solids built from combinations of these

Apply the correct formula depending on what the problem asks for, and use consistent units throughout.

Key termsprismsurface area
Common mistake

A frequent error is mixing units within one calculation, e.g. combining cm and m without converting first.

Must Know

  • Area formulae: triangle 12bh\frac{1}{2}bh; parallelogram bhbh; trapezium 12(a+b)h\frac{1}{2}(a+b)h
  • Circle formulae: circumference 2πr2\pi r or πd\pi d; area πr2\pi r^2
  • Sector area =θ360×πr2= \frac{\theta}{360}\times \pi r^2; arc length =θ360×2πr= \frac{\theta}{360}\times 2\pi r
  • Volume of a prism (including a cylinder) == cross-sectional area ×\times length
  • Know the surface area and volume formulae for spheres, pyramids and cones, and apply them to composite solids
  • Some answers may need to be left in terms of π\pi rather than as a decimal

That's the notes covered.

Carry on to the next subtopic.