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Ratio, Proportion and Rates of Change in AlgebraAQA GCSE Maths: Subtopic test

10 questions, 26 marks

AQA GCSE Maths

Ratio, Proportion and Rates of Change in Algebra

Total 26 marks

Name

Class

Date

  1. 1
    yy is directly proportional to xx. When x=4x = 4, y=20y = 20.
    (a)
    What is the value of the constant of proportionality, kk, where y=kxy = kx?
    [1 mark]
    • A4
    • B5
    • C16
    • D80
    (b)
    Using y=5xy = 5x, find the value of yy when x=7x = 7.
    [1 mark]
    • A12
    • B30
    • C35
    • D40
    (c)
    Which equation correctly relates yy and xx?
    [1 mark]
    • Ay=x5y = \frac{x}{5}
    • By=x+16y = x + 16
    • Cy=20xy = \frac{20}{x}
    • Dy=5xy = 5x

    Total for question 1: 3 marks

  2. 2
    PP is inversely proportional to QQ. When Q=3Q = 3, P=8P = 8.
    (a)
    Find the constant kk in the equation P=kQP = \frac{k}{Q}.
    [2 marks]
    (b)
    Using P=24QP = \frac{24}{Q}, find the value of PP when Q=6Q = 6.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A metal has density 8 g/cm38\,\text{g/cm}^3. For a piece of this metal with volume V cm3V\,\text{cm}^3, the mass MM in grams is given by M=8VM = 8V.
    (a)
    Show that the mass MM in kilograms can be written as M=0.008VM = 0.008V.
    [3 marks]
    (b)
    Using M=0.008VM = 0.008V (with MM in kilograms), find the volume of a piece of this metal with a mass of 2 kg.
    [3 marks]

    Total for question 3: 6 marks

  4. 4
    The time TT (in hours) taken to travel a fixed distance is inversely proportional to the average speed SS (in km/h), so T=kST = \frac{k}{S}, where kk is the distance in km. When S=60S = 60, T=3T = 3.
    (a)
    Find the value of kk, and hence find TT when S=45S = 45.
    [4 marks]
    (b)
    A second, longer journey covers 240 km, with time TT hours related to average speed SS km/h by T=240ST = \frac{240}{S}.

    Find the average speed
    SS needed to complete this journey in T=3.2T = 3.2 hours.
    [4 marks]
    (c)
    A cyclist's speed SS (km/h) is directly proportional to the square root of her power output PP (watts), so S=kPS = k\sqrt{P}. When P=100P = 100 W, S=20S = 20 km/h.

    Find the value of
    kk, calculate the speed when P=225P = 225 W, and hence find the time (to the nearest 0.1 hour) to complete the 180 km journey from part (a) at this speed.
    [5 marks]

    Total for question 4: 13 marks

End of questions