Percentage and GrowthEdexcel GCSE Maths: Revision notes
Section 1
Percentages as Multiplicative Relationships
A percentage change describes a multiplicative relationship between two quantities — one quantity is a fraction or multiple of the other, rather than simply a difference. Expressing a relationship multiplicatively (as a ratio or fraction) is what allows percentage change, scaling and growth to be calculated using a single multiplier.
Example: if a price rises from £80 to £100, the multiplicative relationship is 100/80 = 1.25, meaning the new price is 1.25 times the old one (a 25% increase).
Once you know the multiplier (e.g. 1.25 for a 25% increase), you can apply it directly instead of calculating the percentage and adding it on separately.
Section 2
Direct Proportion as a Model for Growth
When one quantity grows in direct proportion to another, it follows the rule y = kx, where k is a constant multiplier. As x increases, y increases at the same constant rate — this is the simplest model of growth.
Example: if the cost of fuel is directly proportional to the number of litres bought, doubling the litres doubles the cost.
Direct proportion problems are solved by first finding k (using one known pair of values), then using y = kx to find any other value.
If 4 litres of fuel cost £6, then k = 6 ÷ 4 = 1.5, so 10 litres cost 1.5 × 10 = £15.
Section 3
Proportion Equations Beyond y = kx
Growth relationships are not always simple linear proportion. Other common proportion equations include:
- y = kx² (y proportional to the square of x — growth speeds up rapidly)
- y = k√x (y proportional to the square root of x — growth slows down as x increases)
- y = k/x and y = k/x² (inverse proportion — y decreases as x increases)
To solve these, substitute a known pair of values to find k, then use the equation to find unknown values, just as with y = kx.
Do not assume every proportion problem follows y = kx — check whether the question describes proportion to a square, a square root, or an inverse relationship.
Section 4
Expressing One Quantity as a Fraction of Another (Including Over 100%)
To express quantity A as a fraction of quantity B, calculate A ÷ B. This fraction can be:
- Less than 1 (A is smaller than B) — equivalent to a percentage below 100%
- Greater than 1 (A is bigger than B) — equivalent to a percentage above 100%
Example: if A = 120 and B = 80, then A as a fraction of B is 120/80 = 1.5, i.e. 150% — A is one and a half times the size of B, showing growth beyond the original amount.
A fraction or percentage greater than 100% simply means the new quantity is bigger than the original — it is not a mistake.
Section 5
Multi-Step Problems with Fractions, Decimals and Percentages
Growth and percentage problems often require several steps, mixing fractions, decimals and ratios. A reliable method:
- Identify what multiplier or fraction links the quantities
- Convert all values to the same form (decimals are usually easiest for multi-step calculations)
- Apply each step in order, keeping track of what each intermediate answer represents
- Check the final answer makes sense in context (e.g. growth should increase the value)
Example: a quantity increases by 20% then decreases by 10%. Overall multiplier = 1.20 × 0.90 = 1.08, an overall 8% increase (not 10%, since the two percentage changes apply to different amounts).
A percentage increase followed by an equal percentage decrease does NOT return you to the original value — always combine the multipliers rather than adding/subtracting the percentages.
Must Know
- Percentage change is a multiplicative relationship — use a single multiplier (e.g. 1.25 for +25%, 0.90 for −10%)
- Direct proportion (y = kx) is the simplest growth model: find k first, then apply it
- Growth can also follow y = kx², y = k√x, or inverse proportion y = k/x — always check which applies
- A fraction or percentage greater than 100% just means the new value is bigger than the original
- Combine successive percentage changes by multiplying the multipliers, not by adding the percentages
- Always check units and that the final answer makes sense in context
That's the notes covered.
Carry on to the next subtopic.