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Geometry and MeasuresEdexcel GCSE Maths: Topic test

20 questions, 52 marks

Edexcel GCSE Maths

Geometry and Measures topic test

Total 52 marks

Name

Class

Date

  1. 1
    A design team is checking three facts before finalising a garden layout: the interior angle of a regular polygon used for a paved area, the area of a triangular flower bed, and a bearing used for a path.
    (a)
    A regular polygon has 9 sides. What is the size of each interior angle?
    [1 mark]
    • A140°
    • B160°
    • C120°
    • D100°
    (b)
    A triangular flower bed has a base of 8 m and a perpendicular height of 5 m. What is its area?
    [1 mark]
    • A40 m²
    • B13 m²
    • C20 m²
    • D6.5 m²
    (c)
    A path runs on a bearing of 072° from point P to point Q. What is the bearing of P from Q (the back bearing)?
    [1 mark]
    • A108°
    • B252°
    • C072°
    • D288°

    Total for question 1: 3 marks

  2. 2
    Shape PP has vertices A(1,2)A(1, 2), B(4,2)B(4, 2) and C(1,5)C(1, 5). It is translated by the vector (3−2)\binom{3}{-2} to form shape QQ. Two sensor posts, S and T, are placed 6 m apart.
    (a)
    State the coordinates of the image of vertex CC under the translation by (3−2)\binom{3}{-2}.
    [2 marks]
    (b)
    Describe fully the locus of points that are equidistant from S and T.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Triangle XYZXYZ is right-angled at YY, with XY=9XY = 9 cm and YZ=12YZ = 12 cm. In a separate problem, OA→=a\overrightarrow{OA} = \mathbf{a} and OB→=b\overrightarrow{OB} = \mathbf{b}, and MM is the midpoint of ABAB.
    (a)
    Find the length of the hypotenuse XZXZ.
    [3 marks]
    (b)
    Show that OM→=12(a+b)\overrightarrow{OM} = \frac{1}{2}(\mathbf{a} + \mathbf{b}).
    [3 marks]

    Total for question 3: 6 marks

  4. 4
    A landscaper is building a patio and a decorative path. The patio is a composite shape made from a rectangle measuring 10 m by 6 m, with a semicircular section of diameter 6 m removed from one of the 6 m sides. Separately, a ladder of length 7.5 m leans against a vertical wall with its foot 2.4 m from the base of the wall. The path runs on a bearing of 048° for 120 m from point R to point S, then turns and runs on a bearing of 138° for 90 m from S to point T.
    (a)
    Work out the area of the patio, giving your answer correct to 1 decimal place.
    [4 marks]
    (b)
    Find the height up the wall that the ladder reaches, correct to 1 decimal place, and hence find the angle the ladder makes with the ground, correct to 1 decimal place.
    [4 marks]
    (c)
    Work out the distance RTRT, giving your answer to the nearest metre.
    [5 marks]

    Total for question 4: 13 marks

  5. 5
    A design team is checking three facts before finalising a courtyard layout: the interior angle of a regular polygon used for a paved area, the area of a triangular herb bed, and a bearing used for a path.
    (a)
    A regular polygon has 12 sides. What is the size of each interior angle?
    [1 mark]
    • A144°
    • B160°
    • C140°
    • D150°
    (b)
    A triangular herb bed has a base of 10 m and a perpendicular height of 7 m. What is its area?
    [1 mark]
    • A35 m²
    • B70 m²
    • C17.5 m²
    • D24.5 m²
    (c)
    A path runs on a bearing of 115° from point P to point Q. What is the bearing of P from Q (the back bearing)?
    [1 mark]
    • A065°
    • B115°
    • C295°
    • D245°

    Total for question 5: 3 marks

  6. 6
    Shape PP has vertices A(2,1)A(2, 1), B(5,1)B(5, 1) and C(2,4)C(2, 4). It is translated by the vector (−43)\binom{-4}{3} to form shape QQ. Two transmitter masts, F and G, are placed 10 m apart.
    (a)
    State the coordinates of the image of vertex BB under the translation by (−43)\binom{-4}{3}.
    [2 marks]
    (b)
    Describe fully the locus of points that are equidistant from F and G.
    [2 marks]

    Total for question 6: 4 marks

  7. 7
    Triangle DEFDEF is right-angled at EE, with DE=8DE = 8 cm and EF=15EF = 15 cm. In a separate problem, OC→=c\overrightarrow{OC} = \mathbf{c} and OD→=d\overrightarrow{OD} = \mathbf{d}, and NN is the midpoint of CDCD.
    (a)
    Find the length of the hypotenuse DFDF.
    [3 marks]
    (b)
    Show that ON→=12(c+d)\overrightarrow{ON} = \frac{1}{2}(\mathbf{c} + \mathbf{d}).
    [3 marks]

    Total for question 7: 6 marks

  8. 8
    A landscaper is building a courtyard and a decorative path. The courtyard is a composite shape made from a rectangle measuring 12 m by 8 m, with a semicircular section of diameter 8 m removed from one of the 8 m sides. Separately, a ladder of length 8.5 m leans against a vertical wall with its foot 3.0 m from the base of the wall. The path runs on a bearing of 065° for 140 m from point R to point S, then turns and runs on a bearing of 155° for 105 m from S to point T.
    (a)
    Work out the area of the courtyard, giving your answer correct to 1 decimal place.
    [4 marks]
    (b)
    Find the height up the wall that the ladder reaches, correct to 1 decimal place, and hence find the angle the ladder makes with the ground, correct to 1 decimal place.
    [4 marks]
    (c)
    Work out the distance RTRT, giving your answer to the nearest metre.
    [5 marks]

    Total for question 8: 13 marks

End of questions