S1.3 Electron configurationsIB Chemistry HL: Subtopic test
10 questions, 27 marks
IB Chemistry HL
S1.3 Electron configurations
Total 27 marks
Name
Class
Date
- 1Chromium (Z = 24) is used to plate car parts, manganese (Z = 25) compounds are used in batteries, and copper(I) oxide (containing Cu⁺ ions; Cu has Z = 29) is used in anti-fouling paint for ships.(a)What is the ground-state electron configuration of the Cu⁺ ion?[1 mark]
- A[Ar]3d¹⁰
- B[Ar]4s¹3d⁹
- C[Ar]4s²3d⁸
- D[Ar]4s¹3d¹⁰
(b)Which species has the same number of unpaired electrons as a ground-state chromium atom?[1 mark]- AMn²⁺
- BFe
- CV
- DMn⁺
(c)Deduce the number of unpaired electrons in a chromium atom and explain why its configuration is not [Ar]4s²3d⁴.[2 marks]Total for question 1: 4 marks
- 2In the emission spectrum of hydrogen, the series of lines in the ultraviolet region converges to a limit at a wavelength of 91.2 nm. Use c = 3.00 × 10⁸ m s⁻¹, h = 6.63 × 10⁻³⁴ J s and Avogadro's constant = 6.02 × 10²³ mol⁻¹.(a)Which electron transition corresponds to the convergence limit of this series?[1 mark]
- An = 2 → n = 1
- Bn = ∞ → n = 1
- Cn = ∞ → n = 2
- Dn = ∞ → n = 3
(b)What is the frequency of radiation at the convergence limit?[1 mark]- A3.29 × 10⁶ Hz
- B3.04 × 10⁻¹⁶ Hz
- C3.29 × 10¹⁵ Hz
- D2.18 × 10⁻¹⁸ Hz
(c)Calculate the first ionisation energy of hydrogen in kJ mol⁻¹.[2 marks]Total for question 2: 4 marks
- 3The first ionisation energies of the period 3 elements, in kJ mol⁻¹, are: sodium 496, magnesium 738, aluminium 578, silicon 787, phosphorus 1012, sulfur 1000, chlorine 1251 and argon 1521.(a)Explain the general increase in first ionisation energy from sodium to argon.[3 marks](b)Explain the decreases in first ionisation energy from magnesium to aluminium and from phosphorus to sulfur.[4 marks]
Total for question 3: 7 marks
- 4Two unknown elements, X and Y, are both in period 3. The first five successive ionisation energies, in kJ mol⁻¹, are: X: 578, 1817, 2745, 11 577, 14 842. Y: 738, 1451, 7733, 10 543, 13 630. Element Y is in the same group as beryllium and calcium, whose first ionisation energies are 900 and 590 kJ mol⁻¹.(a)Deduce the group and identity of element X from its successive ionisation energies, and explain the pattern in the data, including why each successive ionisation energy is larger than the previous one.[6 marks](b)Deduce the group of Y, and use all the data to explain the trend in first ionisation energy down its group and why Y has a higher first ionisation energy than X.[6 marks]
Total for question 4: 12 marks
End of questions