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Geometry and trigonometryIB Maths: Analysis and Approaches HL: Topic test

20 questions, 54 marks

IB Maths: Analysis and Approaches HL

Geometry and trigonometry topic test

Total 54 marks

Name

Class

Date

  1. 1
    A sector of a circle has centre OO, radius 99 cm, and angle θ=2π5\theta=\dfrac{2\pi}{5} radians.
    (a)
    Find the exact arc length of the sector.
    [1 mark]
    • A18π5\dfrac{18\pi}{5} cm
    • B9π5\dfrac{9\pi}{5} cm
    • C162π5\dfrac{162\pi}{5} cm
    • D18π18\pi cm
    (b)
    Find the exact area of the sector.
    [1 mark]
    • A18π5\dfrac{18\pi}{5} cm2^2
    • B81π5\dfrac{81\pi}{5} cm2^2
    • C162π5\dfrac{162\pi}{5} cm2^2
    • D9π5\dfrac{9\pi}{5} cm2^2
    (c)
    Hence find the exact perimeter of the sector.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    It is given that sin⁡θ=25\sin\theta = \dfrac{2}{5}, where θ\theta is obtuse.
    (a)
    Find the exact value of cos⁡θ\cos\theta.
    [1 mark]
    • A215\dfrac{\sqrt{21}}{5}
    • B−2125-\dfrac{21}{25}
    • C−215-\dfrac{\sqrt{21}}{5}
    • D−2125-\dfrac{\sqrt{21}}{25}
    (b)
    Find the exact value of tan⁡θ\tan\theta.
    [1 mark]
    • A22121\dfrac{2\sqrt{21}}{21}
    • B−52-\dfrac{5}{2}
    • C212\dfrac{\sqrt{21}}{2}
    • D−22121-\dfrac{2\sqrt{21}}{21}
    (c)
    Hence find the exact value of sin⁡2θ\sin2\theta.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A vertical flagpole OTOT stands at corner OO of a horizontal rectangular courtyard OPQROPQR, where OP=24OP=24 m and OR=10OR=10 m, with PP and RR adjacent to OO and QQ diagonally opposite OO.
    (a)
    The flagpole has height OT=15OT=15 m. Find the distance from the top of the flagpole, TT, to the corner QQ, giving your answer to 3 significant figures.
    [3 marks]
    (b)
    Find the angle of elevation of TT from QQ, giving your answer to 1 decimal place.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Relative to an origin OO, points AA, BB and CC have position vectors a=3i−j+2k\mathbf{a}=3\mathbf{i}-\mathbf{j}+2\mathbf{k}, b=i+4j−k\mathbf{b}=\mathbf{i}+4\mathbf{j}-\mathbf{k} and c=−2i+j+5k\mathbf{c}=-2\mathbf{i}+\mathbf{j}+5\mathbf{k}.
    (a)
    (i) Find the vector AB→\overrightarrow{AB}. [2]
    (ii) Find
    ∣AB→∣|\overrightarrow{AB}|, giving your answer in exact form. [2]
    (iii) Find the vector
    AC→\overrightarrow{AC}. [2]
    [6 marks]
    (b)
    (i) Find AB→⋅AC→\overrightarrow{AB}\cdot\overrightarrow{AC}. [2]
    (ii) Hence find the angle
    BA^CB\hat{A}C, giving your answer to the nearest degree. [4]
    [6 marks]

    Total for question 4: 12 marks

  5. 5
    Let θ=5π6\theta = \dfrac{5\pi}{6}.
    (a)
    Find the exact value of sin⁡θ\sin\theta.
    [1 mark]
    • A12\dfrac12
    • B−12-\dfrac12
    • C32\dfrac{\sqrt3}{2}
    • D−32-\dfrac{\sqrt3}{2}
    (b)
    Find the exact value of cos⁡θ\cos\theta.
    [1 mark]
    • A32\dfrac{\sqrt3}{2}
    • B12\dfrac12
    • C−12-\dfrac12
    • D−32-\dfrac{\sqrt3}{2}
    (c)
    Hence find the exact value of tan⁡θ\tan\theta.
    [2 marks]

    Total for question 5: 4 marks

  6. 6
    The angle α\alpha satisfies 0<α<π20<\alpha<\dfrac{\pi}{2} and sec⁡α=135\sec\alpha=\dfrac{13}{5}.
    (a)
    Find the exact value of cos⁡α\cos\alpha.
    [1 mark]
    • A513\dfrac{5}{13}
    • B135\dfrac{13}{5}
    • C1213\dfrac{12}{13}
    • D512\dfrac{5}{12}
    (b)
    Find the exact value of cosec α\text{cosec}\,\alpha.
    [1 mark]
    • A1213\dfrac{12}{13}
    • B135\dfrac{13}{5}
    • C1312\dfrac{13}{12}
    • D513\dfrac{5}{13}
    (c)
    Hence find the exact value of cot⁡α\cot\alpha.
    [2 marks]

    Total for question 6: 4 marks

  7. 7
    It is given that sin⁡A=35\sin A=\dfrac35 and cos⁡B=1213\cos B=\dfrac{12}{13}, where AA and BB are both acute angles.
    (a)
    Find the exact value of sin⁡(A+B)\sin(A+B).
    [3 marks]
    (b)
    Hence, using a symmetry property of the sine function, write down the exact value of sin⁡(π−(A+B))\sin(\pi-(A+B)). Then find the exact value of cos⁡(A+B)\cos(A+B).
    [4 marks]

    Total for question 7: 7 marks

  8. 8
    The line L1L_1 has vector equation r=(2−13)+λ(12−1)\mathbf{r}=\begin{pmatrix}2\\-1\\3\end{pmatrix}+\lambda\begin{pmatrix}1\\2\\-1\end{pmatrix}, and the line L2L_2 has vector equation r=(430)+μ(−112)\mathbf{r}=\begin{pmatrix}4\\3\\0\end{pmatrix}+\mu\begin{pmatrix}-1\\1\\2\end{pmatrix}, where λ,μ∈R\lambda,\mu\in\mathbb{R}.
    (a)
    (i) Show that L1L_1 and L2L_2 do not intersect. [4]
    (ii) Explain why
    L1L_1 and L2L_2 are skew lines. [2]
    [6 marks]
    (b)
    Find the angle between the direction vectors of L1L_1 and L2L_2, giving your answer to the nearest degree, and hence find the acute angle between the lines L1L_1 and L2L_2.
    [6 marks]

    Total for question 8: 12 marks

End of questions