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5.1 Limits and the derivativeIB Maths: Analysis and Approaches SL: Revision notes

Section 1

What is a limit?

A limit is the value that an expression gets closer and closer to as its input approaches some value. We write lim⁡h→0(4+h)=4\lim_{h\to0}(4+h)=4 and read it as 'the limit of 4+h4+h as hh tends to 0 is 4'.

A limit can exist even when the expression itself cannot be evaluated at that point. For example 4h+h2h\frac{4h+h^{2}}{h} is undefined at h=0h=0, but for every other hh it equals 4+h4+h, so its limit as h→0h\to0 is 4.

At SL you only need an informal idea of a limit: formal analytic methods of calculating limits are not required.

Key termslimit
Common mistake

Thinking a limit cannot exist because the expression is undefined at the point. 4h+h2h\frac{4h+h^{2}}{h} is undefined at h=0h=0, but its limit is 4.

Section 2

Estimating a limit from values

You may be given values of an expression as the input gets closer to a point, often from both sides. Look for the value the outputs settle towards.

For the cooling coffee, average rates of change over intervals starting at t=10t=10 were −2.0707, −2.1176, −2.1223-2.0707,\,-2.1176,\,-2.1223, and over intervals ending at t=10t=10 were −2.1768, −2.1282, −2.1234-2.1768,\,-2.1282,\,-2.1234. Both sequences close in on about −2.12-2.12, so this is the estimate of the limit.

The values closest to the point are the most reliable; the widest interval gives the worst estimate.

Key termsestimating a limit
Exam tip

Check the values from both sides. If they approach the same number, that is your estimate; quote it to a sensible accuracy, usually 3 significant figures.

Section 3

Gradient of a curve as a limit

The gradient of a straight line is constant, but the gradient of a curve changes from point to point. To find it at a point PP, take a nearby point QQ on the curve and find the gradient of the chord PQPQ: f(x+h)−f(x)h.\frac{f(x+h)-f(x)}{h}. As QQ slides towards PP (h→0h\to0), the chord approaches the tangent at PP, and its gradient approaches the gradient of the curve at PP.

Example: for f(x)=x2−2xf(x)=x^{2}-2x at x=3x=3, the chord gradient simplifies to 4+h4+h, which tends to 4. So the gradient of the curve at x=3x=3 is 4.

Key termschordtangentgradient of a curve
Common mistake

Forgetting to divide by hh: f(3.1)−f(3)=0.41f(3.1)-f(3)=0.41 is the change in yy, not the gradient. The gradient is 0.410.1=4.1\frac{0.41}{0.1}=4.1.

Example

For y=x3y=x^{3} at x=2x=2: (2+h)3−8h=12+6h+h2→12\frac{(2+h)^{3}-8}{h}=12+6h+h^{2}\to12 as h→0h\to0.

Section 4

The derivative: gradient function and rate of change

The derivative of ff gives the gradient of the curve at every point, so it is also called the gradient function. It is the instantaneous rate of change of one quantity with respect to another.

Notation: if y=f(x)y=f(x), the derivative is written dydx\frac{\mathrm{d}y}{\mathrm{d}x} or f′(x)f'(x). Other letters are used in context: dVdr\frac{\mathrm{d}V}{\mathrm{d}r} is the rate of change of volume with respect to radius, and dsdt\frac{\mathrm{d}s}{\mathrm{d}t} is the rate of change of displacement with respect to time (velocity).

The units of a derivative are (units of the top quantity) per (unit of the bottom quantity), for example m s−1^{-1} or °C per minute. A negative derivative means the quantity is decreasing.

Key termsderivativegradient functionrate of change
Exam tip

Say dTdt=−2.12\frac{\mathrm{d}T}{\mathrm{d}t}=-2.12 in words: 'the temperature is falling at 2.12 °C per minute at this moment'.

Section 5

Average versus instantaneous rate of change

The average rate of change over an interval is the gradient of a chord: change in ychange in x.\frac{\text{change in }y}{\text{change in }x}. The instantaneous rate of change at a point is the gradient of the tangent: the limit of average rates over shorter and shorter intervals.

For a stone falling with s=4.9t2s=4.9t^{2}, the average speed over the first 2 s is 9.8 m s−1^{-1}, but the average speed from t=2t=2 to t=2+ht=2+h is 19.6+4.9h19.6+4.9h, which tends to 19.6 m s−1^{-1}. The speed at the instant t=2t=2 is twice the average over the first 2 seconds.

Key termsaverage rate of changeinstantaneous rate of change
Common mistake

Quoting an average rate over a long interval when the question asks for the rate at an instant.

Must know

  • A limit is the value an expression approaches; estimate it from values on both sides.
  • Gradient of a chord: f(x+h)−f(x)h\frac{f(x+h)-f(x)}{h}; the gradient of the curve is its limit as h→0h\to0.
  • The derivative f′(x)f'(x) or dydx\frac{\mathrm{d}y}{\mathrm{d}x} is the gradient function and the instantaneous rate of change.
  • Give rates with units; a negative rate means decreasing.
  • Formal analytic limit methods are not required at SL.

That's the notes covered.

Carry on to the next subtopic.