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3.6 Trigonometric identitiesIB Maths: Analysis and Approaches SL: Subtopic test

10 questions, 27 marks

IB Maths: Analysis and Approaches SL

3.6 Trigonometric identities

Total 27 marks

Name

Class

Date

  1. 1
    The angle θ\theta is obtuse, and sin⁡θ=513\sin\theta = \frac{5}{13}.
    (a)
    Find the exact value of cos⁡θ\cos\theta.
    [1 mark]
    • A1213\frac{12}{13}
    • B−813-\frac{8}{13}
    • C813\frac{8}{13}
    • D−1213-\frac{12}{13}
    (b)
    Find the exact value of sin⁡2θ\sin 2\theta.
    [1 mark]
    • A120169\frac{120}{169}
    • B1013\frac{10}{13}
    • C−120169-\frac{120}{169}
    • D−60169-\frac{60}{169}
    (c)
    Find the exact value of cos⁡2θ\cos 2\theta.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The angle α\alpha satisfies π<α<3π2\pi < \alpha < \frac{3\pi}{2} and cos⁡α=−23\cos\alpha = -\frac{2}{3}.
    (a)
    Find the exact value of tan⁡α\tan\alpha.
    [1 mark]
    • A−52-\frac{\sqrt{5}}{2}
    • B52\frac{\sqrt{5}}{2}
    • C25\frac{2}{\sqrt{5}}
    • D−25-\frac{2}{\sqrt{5}}
    (b)
    Find the exact value of cos⁡2α\cos 2\alpha.
    [1 mark]
    • A−19-\frac{1}{9}
    • B19\frac{1}{9}
    • C−43-\frac{4}{3}
    • D179\frac{17}{9}
    (c)
    Find the exact value of sin⁡2α\sin 2\alpha.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Let f(x)=sin⁡2x1+cos⁡2xf(x) = \frac{\sin 2x}{1 + \cos 2x}, for 0<x<π20 < x < \frac{\pi}{2}.
    (a)
    Show that f(x)=tan⁡xf(x) = \tan x.
    [3 marks]
    (b)
    Given that cos⁡2x=725\cos 2x = \frac{7}{25}, find the exact value of f(x)f(x).
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A garden sprinkler sends a jet of water from ground level at an angle θ\theta above the horizontal, where 0<θ<π20 < \theta < \frac{\pi}{2}. The water lands a horizontal distance R=20sin⁡2θR = 20\sin 2\theta metres from the sprinkler, and the jet reaches a maximum height of H=10sin⁡2θH = 10\sin^2\theta metres.
    (a)
    The sprinkler is set so that tan⁡θ=12\tan\theta = \frac{1}{2}.
    (i) Find the exact values of
    sin⁡θ\sin\theta and cos⁡θ\cos\theta.
    (ii) Hence find the values of
    RR and HH.
    [6 marks]
    (b)
    (i) Show that HR=14tan⁡θ\frac{H}{R} = \frac{1}{4}\tan\theta.
    (ii) The sprinkler is reset so that the water lands at a horizontal distance equal to three times the maximum height of the jet. Find the exact value of
    cos⁡2θ\cos 2\theta, and state what the sign of your answer tells you about θ\theta.
    [6 marks]

    Total for question 4: 12 marks

End of questions