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Coordinate GeometryCambridge IGCSE Maths: Flashcards

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What is the order of a Cartesian coordinate pair?

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What is the order of a Cartesian coordinate pair?
(x,y)(x, y) — the horizontal (xx) coordinate is always given first.
State the formula for the length of a line segment between (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2).
(x2−x1)2+(y2−y1)2\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
Find the distance between (1,2)(1,2) and (4,6)(4,6).
(4−1)2+(6−2)2=9+16=25=5\sqrt{(4-1)^2+(6-2)^2}=\sqrt{9+16}=\sqrt{25}=5
State the midpoint formula for (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2).
(x1+x22,y1+y22)\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)
Find the midpoint of (2,−3)(2,-3) and (8,5)(8,5).
(5,1)(5, 1)
Why does the distance formula work?
It applies Pythagoras' theorem, treating the horizontal and vertical gaps between the points as the two shorter sides of a right-angled triangle.
What does it mean for three points to be collinear?
They all lie on the same straight line.
How can you check three points are collinear using coordinates?
Calculate the gradient between each pair of points; if all gradients are equal, the points are collinear.
M(4,1)M(4,1) is the midpoint of A(2,−3)A(2,-3) and BB. Find BB.
B=(6,5)B = (6, 5), found by rearranging the midpoint formula for each coordinate.
A common mistake when finding a midpoint is...
Subtracting the coordinates instead of adding them before dividing by 2.
Why must coordinate geometry questions on this platform be solved algebraically?
Because the exam format never includes a diagram to read values from — every answer must come from calculation.
If a line segment has length 0, what does that tell you about the two points?
The two points are the same point (identical coordinates).
Find the length of the segment joining (0,0)(0,0) and (3,4)(3,4).
32+42=25=5\sqrt{3^2+4^2}=\sqrt{25}=5
What two calculations does the midpoint formula perform?
It averages the two xx-coordinates and averages the two yy-coordinates.
A(1,1)A(1,1), B(3,5)B(3,5), C(5,9)C(5,9) — are they collinear? Show why.
Yes: gradient AB=2AB = 2 and gradient BC=2BC = 2, so all three points lie on the same line.