All revision notes topics

Sine, Cosine Rule & Area of TrianglesCambridge IGCSE Maths: Revision notes

Section 1

When can I use the sine and cosine rules?

The sine and cosine rules apply to any triangle, not just right-angled ones. Label a triangle so that each side is lower-case and opposite its matching upper-case angle: side aa opposite angle AA, side bb opposite angle BB, side cc opposite angle CC.

Use the sine rule when you know an angle-side matching pair, plus one more piece of information. Use the cosine rule when you know two sides and the included angle, or all three sides.

Key termsincluded angle

Section 2

How do I use the sine rule?

The sine rule states: asin⁡A=bsin⁡B=csin⁡C\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}

  • To find a missing side: use the rule as written, cross-multiply
  • To find a missing angle: flip the rule to sin⁡Aa=sin⁡Bb=sin⁡Cc\frac{\sin A}{a} = \frac{\sin B}{b} = \frac{\sin C}{c}

Use the sine rule whenever you know a matching angle-side pair plus one other side or angle.

Key termssine rule
Example

In a triangle, A=40°A = 40°, a=8a = 8 cm, B=65°B = 65°. Find bb: b=8sin⁡65°sin⁡40°≈11.3b = \frac{8 \sin 65°}{\sin 40°} \approx 11.3 cm.

Section 3

How do I use the cosine rule?

The cosine rule states: a2=b2+c2−2bccos⁡Aa^2 = b^2 + c^2 - 2bc\cos A

  • Use this form to find a missing side when two sides and the included angle are known
  • Rearrange to find a missing angle when all three sides are known: cos⁡A=b2+c2−a22bc\cos A = \frac{b^2+c^2-a^2}{2bc}
Key termscosine rule
Example

Sides b=7b=7, c=9c=9, angle A=60°A=60°: a2=49+81−2(7)(9)cos⁡60°=130−63=67a^2 = 49+81-2(7)(9)\cos60° = 130-63 = 67, so a≈8.19a \approx 8.19.

Section 4

How do I calculate the area of a triangle without a right angle?

When two sides and the included angle are known, use: Area=12absin⁡C\text{Area} = \frac{1}{2}ab\sin C where CC is the angle between sides aa and bb. This formula is given in the exam.

Key termsarea of a triangle
Example

Sides 6 cm and 9 cm with an included angle of 50°: Area =12(6)(9)sin⁡50°≈20.7= \frac{1}{2}(6)(9)\sin50° \approx 20.7 cm².

Section 5

What about obtuse angles and the ambiguous case?

Sine and cosine values behave differently for obtuse angles (between 90° and 180°):

  • sin⁡θ\sin\theta is positive for both θ\theta and 180°−θ180°-\theta, so the sine rule can give two possible answers for an angle — this is the ambiguous case. Check whether the obtuse version makes sense in context (e.g. angles in a triangle must sum to 180°)
  • cos⁡θ\cos\theta is negative for obtuse angles, so the cosine rule naturally identifies whether an angle is obtuse without ambiguity
Key termsambiguous case
Common mistake

Assuming a calculator's sin⁡−1\sin^{-1} answer is the only solution — always check if 180°−θ180° - \theta also fits the triangle's angle sum.

Must Know

  • Sine rule: asin⁡A=bsin⁡B=csin⁡C\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C} — use with a known angle-side pair
  • Cosine rule: a2=b2+c2−2bccos⁡Aa^2=b^2+c^2-2bc\cos A — use with two sides + included angle, or three sides
  • Area =12absin⁡C= \frac{1}{2}ab\sin C using two sides and the included angle
  • Cosine rule directly reveals obtuse angles (negative cosine); sine rule can be ambiguous for obtuse angles
  • Always check A+B+C=180°A+B+C=180° as a sense-check
  • Sine and cosine rules apply to ANY triangle, not just right-angled ones

That's the notes covered.

Carry on to the next subtopic.