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Graphs of FunctionsEdexcel IGCSE Maths: Subtopic test

10 questions, 26 marks

Edexcel IGCSE Maths

Graphs of Functions

Total 26 marks

Name

Class

Date

  1. 1
    The height, in metres, of a ball thrown into the air is modelled by h=−5t2+20th = -5t^2 + 20t, where tt is the time in seconds after it is thrown.
    (a)
    What is the height of the ball when t=1t = 1?
    [1 mark]
    • A5 m
    • B15 m
    • C20 m
    • D25 m
    (b)
    At what value of tt (other than t=0t = 0) does the ball land (h=0h = 0)?
    [1 mark]
    • At=2t = 2
    • Bt=5t = 5
    • Ct=4t = 4
    • Dt=20t = 20
    (c)
    At what value of tt does the ball reach its maximum height?
    [1 mark]
    • At=1t = 1
    • Bt=2t = 2
    • Ct=4t = 4
    • Dt=10t = 10

    Total for question 1: 3 marks

  2. 2
    The graphs of y=12xy = \frac{12}{x} and y=x−4y = x - 4 intersect at two points.
    (a)
    Show that the xx-coordinates of the points of intersection satisfy the equation x2−4x−12=0x^2 - 4x - 12 = 0.
    [2 marks]
    (b)
    Hence find the coordinates of the two points of intersection.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Curve C has equation y=x3−4xy = x^3 - 4x and line L has equation y=3xy = 3x.
    (a)
    Find all the xx-coordinates of the points of intersection of C and L by solving x3−4x=3xx^3 - 4x = 3x.
    [3 marks]
    (b)
    Find the yy-coordinate of the intersection point where x=7x = \sqrt{7}, giving your answer as a surd in its simplest form.
    [3 marks]

    Total for question 3: 6 marks

  4. 4
    The number of bacteria, NN (in thousands), in a sample after tt hours is modelled by N=t3−6t2+9t+40N = t^3 - 6t^2 + 9t + 40 for 0≤t≤60 \leq t \leq 6.
    (a)
    Calculate NN when t=4t = 4, and state what this value represents in the context of the model.
    [4 marks]
    (b)
    Determine whether the bacteria population is increasing or decreasing between t=4t = 4 and t=5t = 5, by calculating NN at t=5t = 5 and comparing it with your answer to part (a).
    [4 marks]
    (c)
    Find the value(s) of tt in the given domain, other than t=0t = 0, for which N=40N = 40, by solving the equation t3−6t2+9t+40=40t^3 - 6t^2 + 9t + 40 = 40.
    [5 marks]

    Total for question 4: 13 marks

End of questions