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Formulae and FunctionsEdexcel GCSE Maths: Subtopic test

10 questions, 26 marks

Edexcel GCSE Maths

Formulae and Functions

Total 26 marks

Name

Class

Date

  1. 1
    A gym charges membership using the formula C=15m+25C = 15m + 25, where CC is the total cost in pounds and mm is the number of months of membership.
    (a)
    Work out the value of CC when m=6m = 6.
    [1 mark]
    • A£115
    • B£120
    • C£130
    • D£140
    (b)
    A member paid a total of £160. Which equation could be used to find mm?
    [1 mark]
    • A25m+15=16025m + 15 = 160
    • B15m−25=16015m - 25 = 160
    • C15(m+25)=16015(m+25) = 160
    • D15m+25=16015m + 25 = 160
    (c)
    The gym removes the one-off joining fee from the formula. Which formula should now be used to calculate the cost?
    [1 mark]
    • AC=15(m+25)C = 15(m+25)
    • BC=15m+25C = 15m + 25
    • CC=15mC = 15m
    • DC=25mC = 25m

    Total for question 1: 3 marks

  2. 2
    A mobile phone company models the cost of a call lasting tt minutes using the function f(t)=0.05t+10f(t) = 0.05t + 10, where f(t)f(t) is the cost in pence and 1010 pence is a fixed connection charge.
    (a)
    A customer makes a call lasting 200 minutes. Work out the cost of the call, in pence, using f(t)f(t).
    [2 marks]
    (b)
    The company defines a new function g(t)=f(t)−10g(t) = f(t) - 10. Show that g(t)=0.05tg(t) = 0.05t.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The formula F=95C+32F = \frac{9}{5}C + 32 converts a temperature of CC degrees Celsius into FF degrees Fahrenheit. A greenhouse thermostat opens the roof vents automatically once the Celsius temperature rises above 30°C30°C.
    (a)
    Rearrange the formula F=95C+32F = \frac{9}{5}C + 32 to make CC the subject.
    [3 marks]
    (b)
    The thermostat sensor reads F=95F = 95. Using the rearranged formula, work out the Celsius temperature and state whether the roof vents will open.
    [3 marks]

    Total for question 3: 6 marks

  4. 4
    A courier company defines two functions for a parcel of mass xx kg: f(x)=2x+3f(x) = 2x + 3 gives the base delivery cost in pounds, and g(x)=x−1g(x) = x - 1 gives a loyalty-adjusted weight used before the cost is calculated. The composite function h(x)=fg(x)h(x) = fg(x) gives the final delivery charge, in pounds, for a loyalty customer.
    (a)
    Find fg(x)fg(x) and show that h(x)=fg(x)=2x+1h(x) = fg(x) = 2x + 1.
    [4 marks]
    (b)
    Find the inverse function h−1(x)h^{-1}(x) and use it to work out the maximum mass, in kg, of a parcel a customer can send for a budget of £11.
    [4 marks]
    (c)
    Prove that h(x)h(x) is always an odd number for every integer value of xx.
    [5 marks]

    Total for question 4: 13 marks

End of questions