S3.2 Functional groups: Classification of organic compoundsIB Chemistry HL: Subtopic test
10 questions, 27 marks
IB Chemistry HL
S3.2 Functional groups: Classification of organic compounds
Total 27 marks
Name
Class
Date
- 1A research group is studying three compounds: but-2-ene (CH₃CH=CHCH₃), 1,2-dichlorocyclopropane (a three-membered carbon ring with one chlorine atom on each of two adjacent ring carbons) and 2-bromobutane (CH₃CHBrCH₂CH₃).(a)Which compound shows cis–trans isomerism?[1 mark]
- ABut-1-ene
- B2-methylbut-2-ene
- C1,1-dichloroethene
- DBut-2-ene
(b)Which statement about the two enantiomers of 2-bromobutane is correct?[1 mark]- AThey rotate plane-polarised light by equal angles in opposite directions.
- BThey have different boiling points.
- CThey are superimposable mirror images.
- DAn equimolar mixture of the two rotates plane-polarised light more than either pure enantiomer.
(c)Explain why 1,2-dichlorocyclopropane exists as cis and trans isomers.[2 marks]Total for question 1: 4 marks
- 2A technician is labelling bottles in a store room. They include ethanamide (CH₃CONH₂), ethylamine (CH₃CH₂NH₂) and a halogenoalkane with the condensed formula CH₃CH₂CH(CH₃)CH₂Cl.(a)Which functional group is present in ethanamide?[1 mark]
- AAmino
- BAmido
- CHydroxyl
- DCarboxyl
(b)What is the IUPAC name of CH₃CH₂CH(CH₃)CH₂Cl?[1 mark]- A1-chloro-3-methylbutane
- B4-chloro-3-methylbutane
- C1-chloro-2-methylbutane
- D1-chloropentane
(c)Deduce the condensed structural formula and IUPAC name of one position isomer of CH₃CH₂CH(CH₃)CH₂Cl.[2 marks]Total for question 2: 4 marks
- 3An unknown compound W contains only carbon, hydrogen and oxygen. Its infrared spectrum shows a very broad absorption between 2500 and 3000 cm⁻¹ and a strong, sharp absorption at 1710 cm⁻¹. Its mass spectrum has a molecular ion peak at m/z = 74 and fragment peaks at m/z = 57, 45 and 29.(a)Deduce what the infrared absorptions show about the bonds and functional group in W.[3 marks](b)Use the mass spectrum to deduce the structure of W, identifying the species responsible for each fragment peak.[4 marks]
Total for question 3: 7 marks
- 4Two esters, T and U, both have the molecular formula C₄H₈O₂. Their ¹H NMR spectra each show three signals. T: 1.2 ppm (triplet, relative area 3), 2.0 ppm (singlet, relative area 3), 4.1 ppm (quartet, relative area 2). U: 1.1 ppm (triplet, relative area 3), 2.3 ppm (quartet, relative area 2), 3.7 ppm (singlet, relative area 3). Both infrared spectra show a strong absorption at 1740 cm⁻¹ and C–H absorptions near 2900–3000 cm⁻¹, but no broad O–H absorption. The most abundant fragment in the mass spectrum of T is at m/z = 43, and in the mass spectrum of U it is at m/z = 57.(a)Deduce the structure of T, explaining how the number of signals, chemical shifts, relative areas and splitting patterns support your answer.[6 marks](b)Deduce the structure of U. Evaluate how the infrared and mass spectrometry data support the structures of both T and U, including why infrared spectroscopy alone cannot distinguish them.[6 marks]
Total for question 4: 12 marks
End of questions