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5.3 Differentiating polynomialsIB Maths: Applications and Interpretation SL: Subtopic test

10 questions, 27 marks

IB Maths: Applications and Interpretation SL

5.3 Differentiating polynomials

Total 27 marks

Name

Class

Date

  1. 1
    A function is defined by f(x)=4x3−6x2+5x−9f(x)=4x^3-6x^2+5x-9.
    (a)
    Find f′(x)f'(x).
    [1 mark]
    • A12x3−12x2+5x12x^3-12x^2+5x
    • B12x2−12x+512x^2-12x+5
    • C4x4−6x3+5x2−9x4x^4-6x^3+5x^2-9x
    • D12x2−6x+512x^2-6x+5
    (b)
    Find the gradient of the graph of ff at the point where x=3x=3.
    [1 mark]
    • A6060
    • B113113
    • C149149
    • D7777
    (c)
    Find the values of xx at which the gradient of the graph of ff is 55.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A function is defined by g(x)=3x2+4x−2x2g(x)=3x^2+\frac{4}{x}-\frac{2}{x^2}, for x≠0x\neq0.
    (a)
    Find g′(x)g'(x).
    [1 mark]
    • A6x+4x2−4x36x+\frac{4}{x^{2}}-\frac{4}{x^{3}}
    • B6x−4+4x6x-4+\frac{4}{x}
    • C6x−4x2+4x36x-\frac{4}{x^{2}}+\frac{4}{x^{3}}
    • D6x−4x2−4x36x-\frac{4}{x^{2}}-\frac{4}{x^{3}}
    (b)
    Find the gradient of the graph of gg at the point where x=2x=2.
    [1 mark]
    • A11.511.5
    • B12.512.5
    • C1010
    • D10.510.5
    (c)
    Find g′(−1)g'(-1) and state whether gg is increasing or decreasing at x=−1x=-1.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The cost, CC AED, of producing xx items in a day is modelled by C(x)=0.5x3−6x2+40x+200C(x)=0.5x^3-6x^2+40x+200, for 0<x≤200<x\le20. The rate of change of cost, in AED per item, is given by C′(x)C'(x).
    (a)
    (i) Find C′(x)C'(x).
    (ii) Find the rate of change of cost when
    1010 items are produced.
    [3 marks]
    (b)
    The rate of change of cost is 4040 AED per item. Find the number of items produced, justifying your choice of solution.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A closed cylindrical can has volume 500 cm3500\text{ cm}^3 and radius rr cm. Its total surface area, A cm2A\text{ cm}^2, is given by A(r)=2πr2+1000rA(r)=2\pi r^2+\frac{1000}{r}, for r>0r>0.
    (a)
    (i) Write A(r)A(r) with r−1r^{-1} in place of 1000r\frac{1000}{r} and hence find A′(r)A'(r).
    (ii) Find
    A′(5)A'(5).
    (iii) Interpret your answer to (ii).
    [6 marks]
    (b)
    (i) Use your GDC to solve A′(r)=0A'(r)=0.
    (ii) Find the value of
    AA at this value of rr.
    (iii) Find
    A′(3)A'(3), and comment on how the surface area changes either side of your value of rr from (i), using A′(5)=22.8A'(5)=22.8.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).