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1.5 Laws of exponents and introduction to logarithmsIB Maths: Applications and Interpretation SL: Subtopic test

10 questions, 27 marks

IB Maths: Applications and Interpretation SL

1.5 Laws of exponents and introduction to logarithms

Total 27 marks

Name

Class

Date

  1. 1
    In this question, x≠0x\neq0.
    (a)
    Simplify x5×x−8x^{5}\times x^{-8}.
    [1 mark]
    • Ax−3x^{-3}
    • Bx13x^{13}
    • Cx−13x^{-13}
    • Dx3x^{3}
    (b)
    Which expression is equal to (3x)−2(3x)^{-2}?
    [1 mark]
    • A13x2\frac{1}{3x^{2}}
    • B−9x2-9x^{2}
    • C19x2\frac{1}{9x^{2}}
    • Dx29\frac{x^{2}}{9}
    (c)
    Write (2x3)48x5\frac{(2x^{3})^{4}}{8x^{5}} in the form kxnkx^{n}, where kk and nn are integers.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    Logarithms with base 1010 and base ee are the inverse functions of 10x10^{x} and exe^{x}.
    (a)
    Find the value of log⁡100.01\log_{10}0.01.
    [1 mark]
    • A22
    • B−2-2
    • C−100-100
    • D−10-10
    (b)
    Find the value of ln⁡(e3)+log⁡1010\ln\left(e^{3}\right)+\log_{10}10.
    [1 mark]
    • A33
    • B1313
    • Ce3+10e^{3}+10
    • D44
    (c)
    Use your GDC to write down the value of log⁡10250\log_{10}250 and the value of ln⁡250\ln250, each correct to 3 significant figures.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A radioactive substance decays so that its mass, mm grams, after tt years is modelled by m=80e−0.05tm=80e^{-0.05t}.
    (a)
    Write down the initial mass, and use your GDC to find the mass after 10 years.
    [3 marks]
    (b)
    Find the time taken for the mass to fall to 20 g. Give your answer correct to 3 significant figures.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    The pH of a solution is defined as pH=−log⁡10h\mathrm{pH}=-\log_{10}h, where hh is the concentration of hydrogen ions in mol dm−3\mathrm{mol\,dm^{-3}}.
    (a)
    (i) Calculate the pH of a solution with h=3.2×10−4h=3.2\times10^{-4}.
    (ii) A solution has pH
    5.65.6. Find the value of hh.
    (iii) Show that when the pH of a solution decreases by
    11, the value of hh is multiplied by 1010.
    [6 marks]
    (b)
    Solution SS has pH 2.82.8. Solution TT has a hydrogen ion concentration 2525 times that of SS.
    (i) Find
    hh for solution SS.
    (ii) Find
    hh for solution TT.
    (iii) Find the pH of solution
    TT, and state which solution is more acidic.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).