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3.11 Symmetry properties of trigonometric graphsIB Maths: Analysis and Approaches HL: Subtopic test

10 questions, 27 marks

IB Maths: Analysis and Approaches HL

3.11 Symmetry properties of trigonometric graphs

Total 27 marks

Name

Class

Date

  1. 1
    The angle θ\theta satisfies 0<θ<π20<\theta<\frac{\pi}{2} and cos⁡θ=513\cos\theta=\frac{5}{13}.
    (a)
    Find the value of cos⁡(π−θ)\cos(\pi-\theta).
    [1 mark]
    • A−513-\frac{5}{13}
    • B513\frac{5}{13}
    • C1213\frac{12}{13}
    • D−1213-\frac{12}{13}
    (b)
    Find the value of tan⁡(π+θ)\tan(\pi+\theta).
    [1 mark]
    • A−125-\frac{12}{5}
    • B512\frac{5}{12}
    • C125\frac{12}{5}
    • D−512-\frac{5}{12}
    (c)
    Find the exact value of sin⁡(2π−θ)+cos⁡(π2+θ)\sin(2\pi-\theta)+\cos\left(\frac{\pi}{2}+\theta\right).
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    It is given that sin⁡20∘=p\sin 20^\circ = p, where 0<p<10<p<1.
    (a)
    Which of the following is equal to sin⁡160∘\sin 160^\circ?
    [1 mark]
    • A−p-p
    • B1−p1-p
    • C1−p2\sqrt{1-p^{2}}
    • Dpp
    (b)
    Which of the following is equal to cos⁡110∘\cos 110^\circ?
    [1 mark]
    • App
    • B−p-p
    • C1−p2\sqrt{1-p^{2}}
    • D−1−p2-\sqrt{1-p^{2}}
    (c)
    Find an expression for tan⁡200∘\tan 200^\circ in terms of pp.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The function ff is defined by f(x)=sin⁡x+sin⁡3xf(x)=\sin x+\sin 3x, for x∈Rx\in\mathbb{R}.
    (a)
    Show that f(π−x)=f(x)f(\pi-x)=f(x) for all x∈Rx\in\mathbb{R}.
    [3 marks]
    (b)
    (i) Show that ff is an odd function.
    (ii) Write down the equation of a vertical line of symmetry of the graph of
    y=f(x)y=f(x).
    (iii) Hence find the exact values of
    f(5π6)f\left(\frac{5\pi}{6}\right) and f(−5π6)f\left(-\frac{5\pi}{6}\right).
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    The height, hh metres, of a passenger above the ground on a Ferris wheel is modelled by h(t)=20−18cos⁡(πt15)h(t)=20-18\cos\left(\frac{\pi t}{15}\right), where tt is the time in minutes after the passenger boards and 0≤t≤300\le t\le 30. One revolution takes 30 minutes.
    (a)
    (i) Show that h(30−t)=h(t)h(30-t)=h(t), and interpret this result in context.
    (ii) Find the two times at which the passenger is 29 m above the ground.
    [6 marks]
    (b)
    (i) Show that h(t+15)=40−h(t)h(t+15)=40-h(t) for 0≤t≤150\le t\le15.
    (ii) Hence, or otherwise, find the two times at which the passenger is 11 m above the ground.
    [6 marks]

    Total for question 4: 12 marks

End of questions