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3.10 Compound angle identitiesIB Maths: Analysis and Approaches HL: Subtopic test

10 questions, 27 marks

IB Maths: Analysis and Approaches HL

3.10 Compound angle identities

Total 27 marks

Name

Class

Date

  1. 1
    Let A=π4A=\frac{\pi}{4} and B=π6B=\frac{\pi}{6}. Do not use a calculator in this question.
    (a)
    Find the exact value of sin⁡(A+B)\sin(A+B).
    [1 mark]
    • A6−24\frac{\sqrt{6}-\sqrt{2}}{4}
    • B2+12\frac{\sqrt{2}+1}{2}
    • C6+24\frac{\sqrt{6}+\sqrt{2}}{4}
    • D6+22\frac{\sqrt{6}+\sqrt{2}}{2}
    (b)
    Find the exact value of tan⁡(A−B)\tan(A-B).
    [1 mark]
    • A2+32+\sqrt{3}
    • B1−331-\frac{\sqrt{3}}{3}
    • C6−24\frac{\sqrt{6}-\sqrt{2}}{4}
    • D2−32-\sqrt{3}
    (c)
    Find the exact value of cos⁡(2A+B)\cos(2A+B).
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The angle xx satisfies π<x<3π2\pi<x<\frac{3\pi}{2} and tan⁡x=34\tan x=\frac{3}{4}.
    (a)
    Find the exact value of tan⁡2x\tan2x.
    [1 mark]
    • A247\frac{24}{7}
    • B−247-\frac{24}{7}
    • C32\frac{3}{2}
    • D724\frac{7}{24}
    (b)
    Find the exact value of sin⁡2x\sin2x.
    [1 mark]
    • A−2425-\frac{24}{25}
    • B2425\frac{24}{25}
    • C1225\frac{12}{25}
    • D725\frac{7}{25}
    (c)
    Find the exact value of cos⁡(x+π3)\cos\left(x+\frac{\pi}{3}\right).
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The compound angle identities for sin⁡(A+B)\sin(A+B) and cos⁡(A+B)\cos(A+B) are given in the formula booklet. In this question you should derive the results from them.
    (a)
    Use the identity for cos⁡(A+B)\cos(A+B) to show that cos⁡2θ=1−2sin⁡2θ\cos2\theta=1-2\sin^{2}\theta.
    [3 marks]
    (b)
    Hence, by writing 3θ=2θ+θ3\theta=2\theta+\theta, show that sin⁡3θ=3sin⁡θ−4sin⁡3θ\sin3\theta=3\sin\theta-4\sin^{3}\theta.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A painting hangs on a vertical wall. Its bottom edge is 11 m above a visitor's eye level and its top edge is 33 m above eye level. The visitor stands xx m from the wall, where x>0x>0. The angles of elevation from the visitor's eye to the top and bottom edges are α\alpha and β\beta respectively, and the angle the painting subtends at the eye is θ=α−β\theta=\alpha-\beta.
    (a)
    Show that tan⁡θ=2xx2+3\tan\theta=\dfrac{2x}{x^{2}+3}, and hence find the value of θ\theta when x=3x=\sqrt{3}.
    [6 marks]
    (b)
    (i) Show that x2+3≥23 xx^{2}+3\ge2\sqrt{3}\,x for all real xx.\n(ii) Hence show that θ≤π6\theta\le\frac{\pi}{6} for all x>0x>0, and state the distance from the wall at which the painting subtends the greatest angle.
    [6 marks]

    Total for question 4: 12 marks

End of questions