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FunctionsCambridge IGCSE Maths: Revision notes

Section 1

What is a function, domain and range?

A function is a rule that maps every input value to exactly one output value, written using function notation, e.g. f(x)=3x−5f(x) = 3x - 5 or h(x)=2x2+3h(x) = 2x^2 + 3.

  • The domain is the set of all possible input values (xx-values)
  • The range is the set of all possible output values (f(x)f(x)-values) produced
  • To evaluate f(a)f(a), substitute aa in place of xx in the function rule

For example, if f(x)=3x−5f(x) = 3x - 5, then f(4)=3(4)−5=7f(4) = 3(4) - 5 = 7.

Key termsfunctiondomainrange
Exam tip

Treat f(x)f(x) notation exactly like substitution — just replace xx with whatever value or expression is inside the brackets.

Section 2

How do you use mapping diagrams to represent functions?

A mapping diagram shows two lists of values — the inputs (domain) on one side and the outputs (range) on the other — connected by arrows showing which output each input produces.

Each arrow represents one input being mapped to exactly one output, consistent with the definition of a function. If any input appears to map to two different outputs, the relationship is not a function.

Key termsmapping diagram

Section 3

How do you find an inverse function?

The inverse function f−1(x)f^{-1}(x) reverses the effect of f(x)f(x) — it takes an output back to the original input.

To find f−1(x)f^{-1}(x) for f(x)=3x−5f(x) = 3x - 5:

  1. Write y=3x−5y = 3x - 5
  2. Swap xx and yy: x=3y−5x = 3y - 5
  3. Rearrange to make yy the subject: y=x+53y = \frac{x+5}{3}
  4. State the inverse: f−1(x)=x+53f^{-1}(x) = \frac{x+5}{3}
Key termsinverse function
Common mistake

f−1(x)f^{-1}(x) does NOT mean 1f(x)\frac{1}{f(x)} — the −1-1 here is inverse-function notation, not a power.

Section 4

How do you form composite functions?

A composite function applies one function to the result of another. gf(x)gf(x) means "do ff first, then apply gg to the result": gf(x)=g(f(x))gf(x) = g(f(x)).

For example, if f(x)=3x−5f(x) = 3x - 5 and g(x)=x2g(x) = x^2:

gf(x)=g(f(x))=g(3x−5)=(3x−5)2gf(x) = g(f(x)) = g(3x-5) = (3x-5)^2

Whereas fg(x)=f(g(x))=f(x2)=3x2−5fg(x) = f(g(x)) = f(x^2) = 3x^2 - 5 — note that gf(x)≠fg(x)gf(x) \neq fg(x) in general.

Key termscomposite function
Exam tip

Read gf(x)gf(x) from right to left: the function closest to xx is applied first.

Must Know

  • A function maps every input to exactly one output; evaluate f(a)f(a) by substituting aa for xx
  • Domain = possible inputs; range = possible outputs
  • To find f−1(x)f^{-1}(x): write as y=y=, swap xx and yy, then rearrange to make yy the subject
  • f−1(x)f^{-1}(x) is inverse notation, not 1f(x)\frac{1}{f(x)}
  • Composite function gf(x)=g(f(x))gf(x) = g(f(x)) applies ff first, then gg — order matters, so gf(x)≠fg(x)gf(x) \neq fg(x) generally

That's the notes covered.

Carry on to the next subtopic.