All worksheets topics

Simultaneous EquationsCambridge IGCSE Maths: Subtopic test

10 questions, 26 marks

Cambridge IGCSE Maths

Simultaneous Equations

Total 26 marks

Name

Class

Date

  1. 1
    At a market stall, mango and papaya prices satisfy a pair of simultaneous equations.
    (a)
    At a market stall, 2 mangoes and 3 papayas cost 26 dirhams, so 2m+3p=262m + 3p = 26, and 1 mango and 1 papaya cost 10 dirhams, so m+p=10m + p = 10. What is the value of pp?
    [1 mark]
    • Ap=6p = 6
    • Bp=4p = 4
    • Cp=8p = 8
    • Dp=2p = 2
    (b)
    Using the same equations, 2m+3p=262m + 3p = 26 and m+p=10m + p = 10, what is the value of mm?
    [1 mark]
    • Am=8m = 8
    • Bm=6m = 6
    • Cm=3m = 3
    • Dm=4m = 4
    (c)
    A customer buys 3 mangoes and 2 papayas. Using m=4m=4 and p=6p=6, how much does this cost in dirhams?
    [1 mark]
    • A20
    • B24
    • C26
    • D30

    Total for question 1: 3 marks

  2. 2
    A cinema sells adult and child tickets, and two families' purchases give simultaneous equations for the prices.
    (a)
    A cinema sells adult tickets for aa dirhams and child tickets for cc dirhams. One family buys 2 adult and 3 child tickets for 76 dirhams, and another buys 3 adult and 1 child ticket for 72 dirhams. Construct a pair of simultaneous equations to represent this information.
    [2 marks]
    (b)
    Solve the simultaneous equations 2a+3c=762a + 3c = 76 and 3a+c=723a + c = 72 to find the price of an adult ticket, aa, and a child ticket, cc.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A café tracks combined orders of coffee and pastries using simultaneous equations.
    (a)
    A café sells coffees for xx dirhams and pastries for yy dirhams. The equations 5x+2y=315x + 2y = 31 and 3x+4y=273x + 4y = 27 describe two orders. Solve these simultaneous equations using the elimination method, showing full working.
    [3 marks]
    (b)
    Using your solution to part (a), calculate the total cost of 2 coffees and 3 pastries.
    [3 marks]

    Total for question 3: 6 marks

  4. 4
    A rectangular garden's perimeter and area lead to a pair of simultaneous equations, one linear and one non-linear.
    (a)
    A rectangular garden has a perimeter of 34 m, so 2(x+y)=342(x+y) = 34 where xx and yy are the side lengths. The garden's area is 6060 m², so xy=60xy = 60. Form the pair of simultaneous equations (one linear, one non-linear) that represent this situation.
    [4 marks]
    (b)
    Solve the simultaneous equations x+y=17x + y = 17 and xy=60xy = 60 to find both possible pairs of values for xx and yy.
    [4 marks]
    (c)
    A different rectangular garden measures 9 m by 5 m. A path of constant width ww is built around the inside edge, reducing the remaining planting area to 21 m². Form and solve an equation for ww, showing full working, and state which solution is valid in context.
    [5 marks]

    Total for question 4: 13 marks

End of questions