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Powers, Roots & Standard FormEdexcel IGCSE Maths: Revision notes

Section 1

What do negative and fractional powers actually mean?

Index laws extend beyond positive whole numbers. You must be able to evaluate any integer or unit-fraction power without a calculator.

  • Zero index: any non-zero number to the power 0 equals 1, e.g. 50=15^0 = 1
  • Negative index: a−n=1ana^{-n} = \frac{1}{a^n} — it means "reciprocal", not "negative number"
  • Unit fraction index: a1n=ana^{\frac{1}{n}} = \sqrt[n]{a} — the denominator is the root
  • General fraction index: amn=(an)ma^{\frac{m}{n}} = \left(\sqrt[n]{a}\right)^m
ExpressionMeaningValue
2−32^{-3}123\frac{1}{2^3}18\frac{1}{8}
9129^{\frac{1}{2}}9\sqrt{9}33
8238^{\frac{2}{3}}(83)2\left(\sqrt[3]{8}\right)^244
Key termsindex (power)reciprocalunit fraction index
Common mistake

a−na^{-n} does NOT make the number negative — it takes the reciprocal. 2−2=142^{-2} = \frac{1}{4}, not −4-4.

Exam tip

For amna^{\frac{m}{n}}, always root first then power (smaller numbers to deal with): find an\sqrt[n]{a}, then raise the result to the power mm.

Section 2

How do the index laws combine powers?

When multiplying or dividing powers of the same base, combine the indices instead of expanding the numbers.

  • Multiplying: am×an=am+na^m \times a^n = a^{m+n}
  • Dividing: am÷an=am−na^m \div a^n = a^{m-n}
  • Power of a power: (am)n=amn(a^m)^n = a^{mn}
  • Power of a product: (ab)n=anbn(ab)^n = a^n b^n

These laws only apply directly when the bases are identical. If bases differ, try to rewrite one as a power of the other (e.g. 4=224 = 2^2) before combining.

Key termsbaseindex laws
Example

Simplify 27×2324\frac{2^7 \times 2^3}{2^4}: add the top indices then subtract, giving 27+3−4=26=642^{7+3-4} = 2^6 = 64.

Section 3

What does standard form represent and how do you write numbers in it?

Standard form writes very large or very small numbers compactly as: A×10nA \times 10^{n} where 1≤A<101 \le A < 10 and nn is an integer (positive, negative, or zero).

  • Large numbers: nn is positive, e.g. 384,000=3.84×105384{,}000 = 3.84 \times 10^5
  • Small numbers (less than 1): nn is negative, e.g. 0.00021=2.1×10−40.00021 = 2.1 \times 10^{-4}
  • The power of 10 tells you how many places the decimal point moves: right for positive nn, left for negative nn
  • Always check AA is between 1 and 10 — this is the most commonly lost mark
Key termsstandard formcoefficient
Common mistake

Writing 38.4×10438.4 \times 10^4 instead of 3.84×1053.84 \times 10^5 — the coefficient must be less than 10, so always adjust the power of 10 to compensate.

Section 4

How do you add, subtract, multiply and divide numbers in standard form?

Multiplying/dividing: deal with the coefficients and powers of 10 separately, then convert back to standard form if needed. (A×10m)×(B×10n)=(A×B)×10m+n\left(A \times 10^m\right) \times \left(B \times 10^n\right) = (A \times B) \times 10^{m+n} (A×10m)÷(B×10n)=(AB)×10m−n\left(A \times 10^m\right) \div \left(B \times 10^n\right) = \left(\frac{A}{B}\right) \times 10^{m-n}

Adding/subtracting: the powers of 10 must match first — convert one number so both have the same power, then add/subtract the coefficients only.

Use a calculator's standard form (EXP or ×10x\times 10^x) key to check answers, but you must be able to do these by hand.

Key termslike powers
Example

(3×104)+(5×103)(3 \times 10^4) + (5 \times 10^3): rewrite as (30×103)+(5×103)=35×103=3.5×104(30 \times 10^3) + (5 \times 10^3) = 35 \times 10^3 = 3.5 \times 10^4.

Exam tip

After multiplying or dividing, always re-check the coefficient is still between 1 and 10 — you often need to adjust the power of 10 by one at the end.

Section 5

How do surds and roots relate to powers?

Roots are the inverse of powers, and integer/fractional indices link the two topics together.

  • a=a12\sqrt{a} = a^{\frac{1}{2}} and a3=a13\sqrt[3]{a} = a^{\frac{1}{3}}
  • Square rooting a negative number has no real solution — but a negative number cubed gives a negative result, e.g. −83=−2\sqrt[3]{-8} = -2
  • Perfect squares (1, 4, 9, 16, 25...) and perfect cubes (1, 8, 27, 64...) should be known from memory to evaluate roots without a calculator
  • Estimating roots: 50\sqrt{50} lies between 49=7\sqrt{49}=7 and 64=8\sqrt{64}=8, so it is close to 7.1
Key termsrootperfect squareperfect cube
Think of it like this

Powers and roots are opposite operations, like multiplying and dividing — a root "undoes" the corresponding power.

Must Know

  • a0=1a^0 = 1 and a−n=1ana^{-n} = \frac{1}{a^n} for any non-zero aa
  • a1n=ana^{\frac{1}{n}} = \sqrt[n]{a} and amn=(an)ma^{\frac{m}{n}} = \left(\sqrt[n]{a}\right)^m
  • Index laws (same base only): am×an=am+na^m \times a^n = a^{m+n}, am÷an=am−na^m \div a^n = a^{m-n}, (am)n=amn(a^m)^n = a^{mn}
  • Standard form: A×10nA \times 10^n, where 1≤A<101 \le A < 10 and n∈Zn \in \mathbb{Z}
  • To add/subtract in standard form, match the powers of 10 first; to multiply/divide, combine coefficients and add/subtract powers separately
  • Always check the final coefficient is between 1 and 10, adjusting the power of 10 if not

That's the notes covered.

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