All revision notes topics

Set Notation & Venn DiagramsEdexcel IGCSE Maths: Revision notes

Section 1

What is a set and how do we write one?

A set is a well-defined collection of objects, called elements or members.

  • Sets are usually named with capital letters: AA, BB, E\mathscr{E}
  • Elements are listed inside curly brackets: A={1,2,3,4}A = \{1, 2, 3, 4\}
  • x∈Ax \in A means "xx is an element of AA"
  • x∉Ax \notin A means "xx is not an element of AA"
  • n(A)n(A) means "the number of elements in set AA"

Example: If A={2,4,6,8}A = \{2, 4, 6, 8\}, then n(A)=4n(A) = 4, and 4∈A4 \in A but 5∉A5 \notin A.

Key termsSetElementn(A)
Example

If B={prime numbers less than 10}={2,3,5,7}B = \{\text{prime numbers less than } 10\} = \{2, 3, 5, 7\}, then n(B)=4n(B) = 4.

Section 2

What are the universal set, empty set, and subsets?

  • The universal set, E\mathscr{E} (or sometimes UU), contains all elements being considered in a given question.
  • The empty set, written ∅\varnothing or {}\{\}, contains no elements: n(∅)=0n(\varnothing) = 0.
  • AA is a subset of BB, written A⊆BA \subseteq B, if every element of AA is also in BB.
  • AA is a proper subset of BB, written A⊂BA \subset B, if A⊆BA \subseteq B but A≠BA \neq B.

Table of subset symbols:

SymbolMeaning
A⊆BA \subseteq BAA is a subset of BB (could be equal to BB)
A⊂BA \subset BAA is a proper subset of BB (not equal to BB)
A⊄BA \not\subset BAA is not a subset of BB
Key termsUniversal setEmpty setSubsetProper subset
Common mistake

Do not confuse ∈\in (an element belongs to a set) with ⊆\subseteq (one set belongs inside another set) — 3∈A3 \in A but {3}⊆A\{3\} \subseteq A.

Section 3

What do union, intersection, and complement mean?

These three operations combine or restrict sets.

  • Union A∪BA \cup B: everything in AA OR BB (or both) — combine the sets.
  • Intersection A∩BA \cap B: only elements in BOTH AA AND BB — the overlap.
  • Complement A′A': everything in E\mathscr{E} that is NOT in AA.

Key counting rule: n(A∪B)=n(A)+n(B)−n(A∩B)n(A \cup B) = n(A) + n(B) - n(A \cap B)

This avoids double-counting elements that are in both sets.

Example: If E={1,2,3,...,10}\mathscr{E} = \{1,2,3,...,10\}, A={2,4,6,8,10}A = \{2,4,6,8,10\}, B={3,6,9}B = \{3,6,9\}, then:

  • A∪B={2,3,4,6,8,9,10}A \cup B = \{2,3,4,6,8,9,10\}
  • A∩B={6}A \cap B = \{6\}
  • A′={1,3,5,7,9}A' = \{1,3,5,7,9\}
Key termsUnionIntersectionComplement
Exam tip

Remember: ∪\cup (union) looks like a cup that holds everything — think 'combine'. ∩\cap (intersection) looks like an upside-down cup — think 'overlap only'.

Common mistake

A common error is forgetting to subtract n(A∩B)n(A \cap B) once when finding n(A∪B)n(A \cup B), which double-counts the overlap.

Section 4

How do Venn diagrams represent sets?

A Venn diagram shows sets as overlapping circles inside a rectangle representing E\mathscr{E}.

  • The rectangle = universal set E\mathscr{E}
  • Each circle = one set (e.g. AA, BB)
  • The overlapping region = A∩BA \cap B
  • Outside all circles (but inside the rectangle) = elements in neither set, i.e. (A∪B)′(A \cup B)'

Reading numbers from a Venn diagram (two sets): If a diagram shows 5 in the "AA only" region, 3 in the overlap, and 4 in the "BB only" region, with 2 outside both circles, then:

  • n(A)=5+3=8n(A) = 5 + 3 = 8
  • n(B)=3+4=7n(B) = 3 + 4 = 7
  • n(A∩B)=3n(A \cap B) = 3
  • n(A∪B)=5+3+4=12n(A \cup B) = 5 + 3 + 4 = 12
  • n(E)=5+3+4+2=14n(\mathscr{E}) = 5 + 3 + 4 + 2 = 14
Key termsVenn diagram
Think of it like this

Think of two overlapping circles as two friend groups at a party — the overlapping middle is people who know both groups; outside both circles are guests who know neither.

Section 5

How do I solve worded problems using sets?

Exam questions often describe real situations (e.g. students studying subjects) rather than drawing the diagram for you.

Method:

  1. Define what each set represents (e.g. FF = students who study French).
  2. Fill in the intersection region first (the number who satisfy both conditions).
  3. Work outwards to fill in "only AA" and "only BB" regions by subtraction.
  4. Use n(E)n(\mathscr{E}) minus everything placed so far to find the region outside both circles.
  5. Check all regions sum to n(E)n(\mathscr{E}).

Example: In a class of 30, 18 study French (FF), 15 study Spanish (SS), and 8 study both.

  • n(F∩S)=8n(F \cap S) = 8
  • French only =18−8=10= 18 - 8 = 10
  • Spanish only =15−8=7= 15 - 8 = 7
  • Neither =30−(10+8+7)=5= 30 - (10 + 8 + 7) = 5
Exam tip

Always fill in the intersection value first when working from a worded problem — everything else is found by subtraction from there.

Must Know

  • ∈\in means "is an element of"; A⊆BA \subseteq B means "AA is a subset of BB"
  • A∪BA \cup B = everything in AA or BB (combine); A∩BA \cap B = only the overlap
  • A′A' = the complement of AA = everything in E\mathscr{E} not in AA
  • n(A∪B)=n(A)+n(B)−n(A∩B)n(A \cup B) = n(A) + n(B) - n(A \cap B)
  • n(∅)=0n(\varnothing) = 0; the empty set has no elements
  • In worded problems, always find the intersection first, then work outwards by subtraction

That's the notes covered.

Carry on to the next subtopic.