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Algebra ToolkitEdexcel IGCSE Maths: Revision notes

Section 1

What does index notation actually mean?

An index (or power/exponent) tells you how many times a base is multiplied by itself.

an=a×a×⋯×a⏟n timesa^n = \underbrace{a \times a \times \dots \times a}_{n \text{ times}}

For example, 34=3×3×3×3=813^4 = 3 \times 3 \times 3 \times 3 = 81. In algebra the base can be a letter: x5=x×x×x×x×xx^5 = x \times x \times x \times x \times x.

Special cases you must know:

  • a1=aa^1 = a
  • a0=1a^0 = 1 (for any a≠0a \neq 0)
  • a−n=1ana^{-n} = \dfrac{1}{a^n}
  • a1n=ana^{\frac{1}{n}} = \sqrt[n]{a}
Key termsbaseindex/exponentpower
Common mistake

a0=1a^0 = 1, not 00 — students often guess wrong here. Any non-zero number to the power 0 is always 1.

Example

50=15^0 = 1, x0=1x^0 = 1, but 000^0 is undefined for IGCSE purposes.

Section 2

How do the index laws work?

These laws only apply when the bases are the same.

Multiplying: add the indices am×an=am+na^m \times a^n = a^{m+n}

Dividing: subtract the indices am÷an=am−na^m \div a^n = a^{m-n}

Power of a power: multiply the indices (am)n=amn(a^m)^n = a^{mn}

Negative indices: flip to a fraction a−n=1ana^{-n} = \dfrac{1}{a^n}

Fractional indices: roots a1n=an,amn=(an)ma^{\frac{1}{n}} = \sqrt[n]{a}, \qquad a^{\frac{m}{n}} = \left(\sqrt[n]{a}\right)^m

Numbers with different bases (like x3×y2x^3 \times y^2) cannot be combined using these laws.

Key termsindex lawsfractional indexnegative index
Exam tip

Say the law out loud as you use it: 'same base, multiplying, so I ADD the powers.' This stops you mixing up add/subtract/multiply.

Common mistake

x3×x2≠x6x^3 \times x^2 \neq x^6. Do NOT multiply the indices when multiplying terms — add them: x3×x2=x5x^3 \times x^2 = x^5.

Example

a7a3=a7−3=a4\dfrac{a^7}{a^3} = a^{7-3} = a^4; (x2)5=x10(x^2)^5 = x^{10}; 823=(83)2=22=48^{\frac{2}{3}} = (\sqrt[3]{8})^2 = 2^2 = 4.

Section 3

What is substitution and how do you do it accurately?

Substitution means replacing letters in an expression with given numerical values and then evaluating.

Method:

  1. Write out the expression.
  2. Replace each letter with its value in brackets.
  3. Apply BIDMAS (Brackets, Indices, Division/Multiplication, Addition/Subtraction) to simplify.

Example: find the value of 2x2−3y2x^2 - 3y when x=−3x = -3 and y=4y = 4. 2(−3)2−3(4)=2(9)−12=18−12=62(-3)^2 - 3(4) = 2(9) - 12 = 18 - 12 = 6

Using brackets around substituted values is essential, especially with negative numbers, so you don't lose a minus sign or misapply an index.

Key termssubstitutionBIDMAS
Common mistake

(−3)2=9(-3)^2 = 9, not −9-9. Squaring a negative number always gives a positive result — the brackets matter.

Exam tip

Always substitute negative numbers in brackets: write (−3)(-3) not just −3-3, especially before an index.

Think of it like this

Think of substitution like a fill-in-the-blank template: the expression is the sentence structure, and you're just swapping in the given values without changing the structure.

Section 4

How do you collect like terms correctly?

Like terms have exactly the same letter(s) raised to exactly the same power(s). Only like terms can be added or subtracted.

3x+5x=8x7y2−2y2=5y23x + 5x = 8x \qquad 7y^2 - 2y^2 = 5y^2

But 3x3x and 5x25x^2 are not like terms (different powers), and 3x3x and 3y3y are not like terms (different letters).

Method for simplifying an expression:

  1. Identify groups of like terms.
  2. Add/subtract the coefficients within each group, keeping the letter part unchanged.
  3. Write the simplified expression, usually in descending order of powers.

Example: simplify 4x2+3x−2x2+7−5x4x^2 + 3x - 2x^2 + 7 - 5x. =(4x2−2x2)+(3x−5x)+7=2x2−2x+7= (4x^2 - 2x^2) + (3x - 5x) + 7 = 2x^2 - 2x + 7

Key termslike termscoefficientterm
Common mistake

3x+5x23x + 5x^2 cannot be simplified to 8x28x^2 or 8x38x^3 — different powers of xx are different terms and stay separate.

Exam tip

Underline or colour-code matching terms before combining them, especially in longer expressions with several letters.

Must Know

  • a0=1a^0 = 1 for any non-zero aa; a−n=1ana^{-n} = \dfrac{1}{a^n}
  • Multiplying same-base powers: ADD indices. Dividing: SUBTRACT indices. Power of a power: MULTIPLY indices.
  • amn=(an)ma^{\frac{m}{n}} = \left(\sqrt[n]{a}\right)^m
  • Always substitute values in brackets, especially negatives, before applying BIDMAS
  • Only like terms (same letters, same powers) can be combined by adding/subtracting coefficients
  • Index laws only work when the bases are identical

That's the notes covered.

Carry on to the next subtopic.