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Algebra ToolkitEdexcel IGCSE Maths: Subtopic test

10 questions, 26 marks

Edexcel IGCSE Maths

Algebra Toolkit

Total 26 marks

Name

Class

Date

  1. 1
    A toy company designs three number machines. Machine 1 takes an input xx, doubles it, then adds 5. Machine 2 takes the output of Machine 1 and multiplies the whole result by 3. Machine 3 is used separately to collect like terms in an expression the engineers write down: 4x2+3x−x2+5x4x^2 + 3x - x^2 + 5x.
    (a)
    Find the output of the first machine when the input is x=4x = 4.
    [1 mark]
    • A9
    • B13
    • C14
    • D20
    (b)
    Which expression is equivalent to 3(2x+5)3(2x+5), the result of passing Machine 1's output through Machine 2?
    [1 mark]
    • A6x+56x+5
    • B6x+156x+15
    • C5x+155x+15
    • D6x+86x+8
    (c)
    Machine 3 collects like terms in 4x2+3x−x2+5x4x^2 + 3x - x^2 + 5x. What is the simplified result?
    [1 mark]
    • A3x2+2x3x^2+2x
    • B3x2+8x3x^2+8x
    • C4x2+8x4x^2+8x
    • D5x2+8x5x^2+8x

    Total for question 1: 3 marks

  2. 2
    A market trader values his stock of boxes using the formula V=3n2−2nV = 3n^2 - 2n, where nn is the number of boxes and VV is the value in dollars.
    (a)
    Evaluate VV when n=5n = 5.
    [2 marks]
    (b)
    The trader doubles his stock and adds a further 4n4n dollars of value. Simplify 2(3n2−2n)+4n2(3n^2-2n) + 4n fully by collecting like terms.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A laboratory records bacteria growth using powers of a base value. A technician must simplify expressions combining these powers using the index laws am×an=am+na^m \times a^n = a^{m+n}, am÷an=am−na^m \div a^n = a^{m-n} and (am)n=amn(a^m)^n = a^{mn}.
    (a)
    Simplify fully a7×a3a4\frac{a^7 \times a^3}{a^4}, showing each index law used.
    [3 marks]
    (b)
    Given that b0=1b^0 = 1, simplify b5×b−2b0\frac{b^5 \times b^{-2}}{b^0}, giving your answer in the form bnb^n.
    [3 marks]

    Total for question 3: 6 marks

  4. 4
    A fitness instructor tracks a client's heart rate recovery after exercise using the formula H=180−2tH = 180-2t, where HH is the heart rate in beats per minute and tt is the number of minutes since exercise stopped. A second client's recovery is given by 170−3t170-3t. A third client's heart rate decay factor involves powers of a constant kk.
    (a)
    Evaluate HH when t=12t = 12, and state whether the heart rate has dropped below 150 beats per minute, showing full working.
    [4 marks]
    (b)
    The combined recovery expression for the first two clients is (180−2t)+(170−3t)(180-2t)+(170-3t). Simplify this fully by collecting like terms.
    [4 marks]
    (c)
    A third client's heart rate decay factor is given by k3×k−5÷k−4k^3 \times k^{-5} \div k^{-4}, where kk represents a constant related to fitness level. Simplify this expression fully, showing each index law step, and state the final power of kk.
    [5 marks]

    Total for question 4: 13 marks

End of questions