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Mass spectrometry in organic analysisAQA A-Level Chemistry: Subtopic test

10 questions, 27 marks

AQA A-Level Chemistry

Mass spectrometry in organic analysis

Total 27 marks

Name

Class

Date

  1. 1
    A pure organic compound is analysed by mass spectrometry. In the mass spectrum, the peak with the highest mass-to-charge ratio (ignoring any very small peaks above it) is at m/z = 74.
    (a)
    What does the peak at m/z = 74 represent?
    [1 mark]
    • AThe molecular ion, which gives the relative molecular mass
    • BThe base peak, which is the fragment with the most atoms
    • CA fragment ion formed by loss of a hydrogen atom
    • DThe ion formed by the carbon-13 isotope only
    (b)
    Which compound could give this molecular ion peak?
    [1 mark]
    • APropan-2-ol, C₃H₈O
    • BButanal, C₄H₈O
    • CButan-2-ol, C₄H₁₀O
    • D2-Methylpropanal, C₄H₈O
    (c)
    The compound is known to contain only carbon, hydrogen and oxygen. Explain why the m/z value of 74 alone cannot be used to find its molecular formula.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    High-resolution mass spectrometry measures relative molecular masses to four decimal places. Precise relative atomic masses: H = 1.0078, C = 12.0000, N = 14.0031, O = 15.9949.
    (a)
    Why do compounds with the same whole-number relative molecular mass have different precise relative molecular masses?
    [1 mark]
    • AThey contain different numbers of electrons
    • BThe precise masses of atoms are not whole numbers, so different combinations of atoms give different totals
    • CThe molecular ion loses mass as it travels through the spectrometer
    • DThey have different numbers of neutrons in each molecule
    (b)
    What is the precise relative molecular mass of propan-1-ol, C₃H₈O?
    [1 mark]
    • A60.0000
    • B60.0210
    • C59.0495
    • D60.0573
    (c)
    A compound has a precise relative molecular mass of 46.0054. Calculate the precise relative molecular masses of C₂H₆O and CH₂O₂ and decide which is the molecular formula of the compound.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A pharmaceutical analyst finds that a compound containing only carbon, hydrogen and oxygen has a precise relative molecular mass of 88.0524 by high-resolution mass spectrometry. Precise relative atomic masses: H = 1.0078, C = 12.0000, O = 15.9949.
    (a)
    The compound has a nominal mass of 88. Calculate the precise relative molecular masses of C₄H₈O₂ and C₅H₁₂O and deduce the molecular formula of the compound.
    [3 marks]
    (b)
    The compound fizzes when added to aqueous sodium carbonate. Identify the functional group and give the names and structural formulae of two possible isomers. Explain why high-resolution mass spectrometry cannot tell these two isomers apart.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A forensic laboratory uses high-resolution mass spectrometry to identify unknown substances. Precise relative atomic masses: H = 1.0078, C = 12.0000, N = 14.0031, O = 15.9949.
    (a)
    A gas from a sealed container has a molecular ion peak at m/z = 28.0313. The gas could be carbon monoxide, nitrogen or ethene. Calculate the precise relative molecular mass of each, deduce the gas, and explain why a low-resolution spectrometer could not identify it.
    [6 marks]
    (b)
    A laboratory technician says that a molecular ion peak at m/z = 72 proves that a liquid is butanal, C₄H₈O. Evaluate this claim, using precise relative molecular masses of other possible formulae and the structure of the compound.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).