Mass spectrometry in organic analysisAQA A-Level Chemistry: Subtopic test
10 questions, 27 marks
AQA A-Level Chemistry
Mass spectrometry in organic analysis
Total 27 marks
Name
Class
Date
- 1A pure organic compound is analysed by mass spectrometry. In the mass spectrum, the peak with the highest mass-to-charge ratio (ignoring any very small peaks above it) is at m/z = 74.(a)What does the peak at m/z = 74 represent?[1 mark]
- AThe molecular ion, which gives the relative molecular mass
- BThe base peak, which is the fragment with the most atoms
- CA fragment ion formed by loss of a hydrogen atom
- DThe ion formed by the carbon-13 isotope only
(b)Which compound could give this molecular ion peak?[1 mark]- APropan-2-ol, C₃H₈O
- BButanal, C₄H₈O
- CButan-2-ol, C₄H₁₀O
- D2-Methylpropanal, C₄H₈O
(c)The compound is known to contain only carbon, hydrogen and oxygen. Explain why the m/z value of 74 alone cannot be used to find its molecular formula.[2 marks]Total for question 1: 4 marks
- 2High-resolution mass spectrometry measures relative molecular masses to four decimal places. Precise relative atomic masses: H = 1.0078, C = 12.0000, N = 14.0031, O = 15.9949.(a)Why do compounds with the same whole-number relative molecular mass have different precise relative molecular masses?[1 mark]
- AThey contain different numbers of electrons
- BThe precise masses of atoms are not whole numbers, so different combinations of atoms give different totals
- CThe molecular ion loses mass as it travels through the spectrometer
- DThey have different numbers of neutrons in each molecule
(b)What is the precise relative molecular mass of propan-1-ol, C₃H₈O?[1 mark]- A60.0000
- B60.0210
- C59.0495
- D60.0573
(c)A compound has a precise relative molecular mass of 46.0054. Calculate the precise relative molecular masses of C₂H₆O and CH₂O₂ and decide which is the molecular formula of the compound.[2 marks]Total for question 2: 4 marks
- 3A pharmaceutical analyst finds that a compound containing only carbon, hydrogen and oxygen has a precise relative molecular mass of 88.0524 by high-resolution mass spectrometry. Precise relative atomic masses: H = 1.0078, C = 12.0000, O = 15.9949.(a)The compound has a nominal mass of 88. Calculate the precise relative molecular masses of C₄H₈O₂ and C₅H₁₂O and deduce the molecular formula of the compound.[3 marks](b)The compound fizzes when added to aqueous sodium carbonate. Identify the functional group and give the names and structural formulae of two possible isomers. Explain why high-resolution mass spectrometry cannot tell these two isomers apart.[4 marks]
Total for question 3: 7 marks
- 4A forensic laboratory uses high-resolution mass spectrometry to identify unknown substances. Precise relative atomic masses: H = 1.0078, C = 12.0000, N = 14.0031, O = 15.9949.(a)A gas from a sealed container has a molecular ion peak at m/z = 28.0313. The gas could be carbon monoxide, nitrogen or ethene. Calculate the precise relative molecular mass of each, deduce the gas, and explain why a low-resolution spectrometer could not identify it.[6 marks](b)A laboratory technician says that a molecular ion peak at m/z = 72 proves that a liquid is butanal, C₄H₈O. Evaluate this claim, using precise relative molecular masses of other possible formulae and the structure of the compound.[6 marks]
Total for question 4: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).