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Gibbs free-energy change and feasibilityAQA A-Level Chemistry: Subtopic test

10 questions, 27 marks

AQA A-Level Chemistry

Gibbs free-energy change and feasibility

Total 27 marks

Name

Class

Date

  1. 1
    Whether a reaction is feasible at a given temperature depends on the balance between its enthalpy change and its entropy change, expressed by the equation ΔG = ΔH − TΔS, where T is the temperature in kelvin. A student has values of ΔH in kJ mol⁻¹ and ΔS in J K⁻¹ mol⁻¹ for several reactions.
    (a)
    Which statement gives the condition for a reaction to be feasible?
    [1 mark]
    • AΔG must be positive
    • BΔG must be zero or negative
    • CΔH must be negative
    • DΔS must be negative
    (b)
    To use ΔG = ΔH − TΔS correctly with these units, what must the student do?
    [1 mark]
    • AUse the values as they are
    • BMultiply ΔS by 1000
    • CConvert the temperature to °C
    • DDivide ΔS by 1000 to convert it to kJ K⁻¹ mol⁻¹
    (c)
    A reaction has a negative ΔH and a positive ΔS. State the sign of ΔG at all temperatures and explain your answer.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    Dinitrogen tetroxide decomposes reversibly: N₂O₄(g) → 2NO₂(g). For this reaction ΔH = +57.0 kJ mol⁻¹ and ΔS = +176 J K⁻¹ mol⁻¹.
    (a)
    Calculate ΔG for the decomposition of N₂O₄ at 298 K.
    [1 mark]
    • A−4.6 kJ mol⁻¹
    • B+109.4 kJ mol⁻¹
    • C+4.6 kJ mol⁻¹
    • D−52 391 kJ mol⁻¹
    (b)
    Above which temperature is the decomposition of N₂O₄ feasible?
    [1 mark]
    • A324 K
    • B0.324 K
    • C51 K
    • D3.09 × 10⁻³ K
    (c)
    Use the equation ΔG = ΔH − TΔS to explain why increasing the temperature makes the decomposition of N₂O₄ more feasible.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    In the Haber process, N₂(g) + 3H₂(g) → 2NH₃(g), the enthalpy change is ΔH = −92 kJ mol⁻¹ and the entropy change is ΔS = −199 J K⁻¹ mol⁻¹ for the reaction as written.
    (a)
    Calculate ΔG for the Haber process at 298 K. State whether the reaction is feasible at this temperature.
    [3 marks]
    (b)
    Calculate the temperature above which the Haber process is no longer feasible. Explain why the reaction becomes less feasible at higher temperatures.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Iron(II) oxide can be reduced by carbon in a furnace: FeO(s) + C(s) → Fe(s) + CO(g). For this reaction ΔH = +161 kJ mol⁻¹ and ΔS = +158 J K⁻¹ mol⁻¹. The furnace operates at 1300 K.
    (a)
    Calculate the minimum temperature at which carbon can reduce iron(II) oxide, and explain why the reduction becomes feasible only above this temperature.
    [6 marks]
    (b)
    Calculate ΔG for the reduction at 800 K and at 1300 K. Evaluate whether the furnace is suitable for producing iron by this reaction.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).