Arrhenius equationAQA A-Level Chemistry: Subtopic test
10 questions, 27 marks
AQA A-Level Chemistry
Arrhenius equation
Total 27 marks
Name
Class
Date
- 1A food scientist is studying how quickly a vitamin breaks down in fruit juice during storage. The breakdown is a first order reaction with an activation energy of 85.0 kJ mol⁻¹. Take the gas constant R as 8.31 J K⁻¹ mol⁻¹.(a)Which statement best explains why the rate constant for the breakdown increases when the juice is stored at a higher temperature?[1 mark]
- AThe activation energy of the reaction decreases as the temperature rises
- BThe collisions become more frequent, and this alone accounts for the increase in k
- CA greater fraction of the molecules has energy equal to or greater than the activation energy
- DThe concentration of the vitamin increases
(b)What is the value of the term e^(−Ea/RT) at 298 K?[1 mark]- A1.2 × 10⁻¹⁵
- B1.2 × 10¹⁵
- C0.97
- D3.8 × 10⁻¹⁵
(c)The storage temperature of the juice rises from 298 K to 308 K. Calculate the factor by which the rate constant increases.[2 marks]Total for question 1: 4 marks
- 2A student measures the rate constant, k, for the hydrolysis of an ester (reaction X) at five temperatures and plots ln k on the vertical axis against 1/T on the horizontal axis, where T is in kelvin. The line is straight, with a gradient of −8.9 × 10³ K. For a second reaction, Y, the equivalent line has a gradient of −5.2 × 10³ K. Take the gas constant R as 8.31 J K⁻¹ mol⁻¹.(a)Which pair of quantities gives a straight line for reaction X?[1 mark]
- Ak against T
- Bln k against T
- Ck against 1/T
- Dln k against 1/T
(b)Which comparison of reactions X and Y is correct?[1 mark]- AY has the larger activation energy because its gradient is less steep
- BX has the larger activation energy, so its rate constant is more sensitive to a change in temperature
- CX and Y have the same activation energy because both lines are straight
- DY is faster at every temperature because its gradient is smaller
(c)Calculate the activation energy of reaction X in kJ mol⁻¹.[2 marks]Total for question 2: 4 marks
- 3The first order decomposition of compound Z in solution has an Arrhenius constant, A, of 4.5 × 10¹³ s⁻¹ and an activation energy, Ea, of 110 kJ mol⁻¹. Take the gas constant R as 8.31 J K⁻¹ mol⁻¹.(a)Calculate the value of the rate constant for the decomposition of Z at 350 K.[3 marks](b)Calculate the temperature, in K, at which the rate constant for the decomposition of Z is 1.0 × 10⁻² s⁻¹.[4 marks]
Total for question 3: 7 marks
- 4A chemist studies the first order decomposition of a compound in solution at several temperatures. The rate constant, k, is in s⁻¹ and the temperature, T, is in kelvin. Take the gas constant R as 8.31 J K⁻¹ mol⁻¹.(a)A rise in temperature of only 10 K often causes the rate constant to roughly double or triple. Explain, with reference to the Maxwell–Boltzmann distribution and the Arrhenius equation, why a small increase in temperature has such a large effect on k.[6 marks](b)The chemist plots ln k against 1/T. Two points on the straight line are (1/T = 3.30 × 10⁻³ K⁻¹, ln k = −5.10) and (1/T = 2.90 × 10⁻³ K⁻¹, ln k = −2.12). Determine the activation energy in kJ mol⁻¹ and the Arrhenius constant, A, including its units.[6 marks]
Total for question 4: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).