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P2: Exponentials and logarithmsEdexcel International A Level Maths: Topic test

20 questions, 54 marks

Edexcel International A Level Maths

P2: Exponentials and logarithms topic test

Total 54 marks

Name

Class

Date

  1. 1
    The curve y=k×2xy=k\times2^x, where kk is a constant, passes through the point (3,40)(3,40).
    (a)
    Find the value of kk.
    [1 mark]
    • A55
    • B203\frac{20}{3}
    • C320320
    • D2020
    (b)
    What is the value of yy when x=−2x=-2?
    [1 mark]
    • A−20-20
    • B54\frac54
    • C2020
    • D120\frac1{20}
    (c)
    Find the value of xx at which the curve meets the line y=80y=80.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    P=2log⁡36−log⁡34+12log⁡381P=2\log_3 6-\log_3 4+\frac12\log_3 81.
    (a)
    Find the exact value of 2log⁡36−log⁡342\log_3 6-\log_3 4.
    [1 mark]
    • A11
    • Blog⁡332\log_3 32
    • C22
    • Dlog⁡336log⁡34\dfrac{\log_3 36}{\log_3 4}
    (b)
    Find the exact value of 12log⁡381\frac12\log_3 81.
    [1 mark]
    • A40.540.5
    • B44
    • C12\frac12
    • D22
    (c)
    Given that log⁡3x=P+log⁡32\log_3 x=P+\log_3 2, find the value of xx.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The concentration of a drug in a patient's blood is modelled by C=40×0.82tC=40\times0.82^t mg l−1^{-1}, where tt is the time in hours after the drug is given.
    (a)
    Find the time taken for the concentration to fall to 55 mg l−1^{-1}, giving your answer to 33 significant figures.
    [3 marks]
    (b)
    A second dose is given when the concentration falls to 1212 mg l−1^{-1}. Find, to the nearest minute, how many hours and minutes after the first dose this happens.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    f(x)=22x−9×2x+8\mathrm{f}(x)=2^{2x}-9\times2^{x}+8.
    (a)
    Solve f(x)=0\mathrm{f}(x)=0.
    [6 marks]
    (b)
    Find the minimum value of f(x)\mathrm{f}(x), and show that it occurs when x=2log⁡23−1x=2\log_2 3-1.
    [6 marks]

    Total for question 4: 12 marks

  5. 5
    The value, in pounds, of a machine tt years after it was bought is modelled by V=12000×0.85tV=12000\times0.85^t.
    (a)
    What is the value of the machine after 44 years, to the nearest pound?
    [1 mark]
    • A£4800
    • B£6264
    • C£40800
    • D£10200
    (b)
    Which statement about this model is correct?
    [1 mark]
    • AThe value is never zero but gets as close to zero as we like.
    • BThe value falls by £1800 every year.
    • CThe value becomes negative for large tt.
    • DThe value halves every 44 years.
    (c)
    Find the time taken for the value of the machine to fall to half of its original value, giving your answer to 33 significant figures.
    [2 marks]

    Total for question 5: 4 marks

  6. 6
    Consider the equation log⁡2(x+6)−log⁡2(x−2)=3\log_2(x+6)-\log_2(x-2)=3.
    (a)
    Which expression is equal to the left-hand side of the equation?
    [1 mark]
    • Alog⁡28\log_2 8
    • Blog⁡2(x+6)log⁡2(x−2)\dfrac{\log_2(x+6)}{\log_2(x-2)}
    • Clog⁡2[(x+6)(x−2)]\log_2\left[(x+6)(x-2)\right]
    • Dlog⁡2x+6x−2\log_2\dfrac{x+6}{x-2}
    (b)
    What is the solution of the equation?
    [1 mark]
    • Ax=3x=3
    • Bx=87x=\frac87
    • Cx=227x=\frac{22}{7}
    • Dx=6x=6
    (c)
    Explain why the equation can have no solution with x<2x<2, and verify that the solution found in part (b) satisfies the original equation.
    [2 marks]

    Total for question 6: 4 marks

  7. 7
    The number of subscribers to a streaming service is modelled by S=50000×atS=50000\times a^t, where tt is the number of years after launch and aa is a positive constant. After 22 years there are 7200072000 subscribers.
    (a)
    Find the value of aa.
    [3 marks]
    (b)
    Find the number of subscribers after 55 years, to the nearest hundred, and the time for the number of subscribers to reach 200000200000, giving your answer in years to 22 decimal places.
    [4 marks]

    Total for question 7: 7 marks

  8. 8
    Two cultures of bacteria are grown. After tt hours the populations are A=200×2tA=200\times2^{t} and B=1600×1.5tB=1600\times1.5^{t}.
    (a)
    Find the time at which the two populations are equal, to 33 significant figures, and the population at that time to the nearest hundred.
    [6 marks]
    (b)
    Use logarithms to base 1010 to show that log⁡10A=tlog⁡102+log⁡10200\log_{10}A=t\log_{10}2+\log_{10}200, and hence find the time at which AA first exceeds 10610^6, giving your answer to 33 significant figures.
    [6 marks]

    Total for question 8: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).