Hooke's law and force-extension graphsEdexcel A-Level Physics: Subtopic test
10 questions, 27 marks
Edexcel A-Level Physics
Hooke's law and force-extension graphs
Total 27 marks
Name
Class
Date
- 1A helical spring obeys Hooke's law. A tensile force of 4.0 N extends it by 25 mm.(a)What is the stiffness of the spring?[1 mark]
- A160 N m⁻¹
- B6.3 × 10⁻³ N m⁻¹
- C0.16 N m⁻¹
- D16 N m⁻¹
(b)What extension would a tensile force of 10 N produce, assuming the spring still obeys Hooke's law?[1 mark]- A6.3 mm
- B40 mm
- C62.5 mm
- D625 mm
(c)The spring is instead compressed by 15 mm. Calculate the force needed, assuming Hooke's law is obeyed in compression.[2 marks]Total for question 1: 4 marks
- 2A metal wire is loaded in steps and the extension is measured. The graph of force against extension is a straight line through the origin up to a force of 12 N, where the extension is 1.5 mm. Beyond 12 N the line curves so that its gradient decreases. When the wire is unloaded from a force of 12 N it returns to its original length. When it is unloaded from a force of 14 N it is found to be 0.30 mm longer than at the start.(a)What does the graph show at a force of 12 N?[1 mark]
- AThe wire breaks
- BThe limit of proportionality: beyond it, force is no longer proportional to extension
- CThe wire starts to obey Hooke's law
- D12 N is the largest force the wire can ever support
(b)What is the stiffness of the wire in its straight-line region?[1 mark]- A1.3 × 10⁻⁴ N m⁻¹
- B8.0 N m⁻¹
- C8.0 × 10⁶ N m⁻¹
- D8.0 × 10³ N m⁻¹
(c)Explain what the 0.30 mm permanent extension shows about the wire.[2 marks]Total for question 2: 4 marks
- 3A car suspension spring has a stiffness of 4.5 × 10⁴ N m⁻¹. When the car is parked, the spring supports one quarter of the car's mass of 1200 kg. The spring obeys Hooke's law up to a compression of 0.18 m. Take g = 9.81 N kg⁻¹.(a)Calculate the compression of the spring when the car is parked.[3 marks](b)Calculate the largest extra mass the spring can carry, in addition to its share of the car, before its limit of proportionality is reached.[4 marks]
Total for question 3: 7 marks
- 4A steel wire is loaded until it breaks. The force–extension graph is a straight line through the origin up to a force of 400 N, which is the limit of proportionality. The elastic limit is only just above this force. At 450 N the wire reaches its yield point, where it extends a large amount for very little increase in force. The force then rises to a maximum of 520 N and the wire breaks.(a)Describe and explain how the wire behaves as the force is increased from zero to 480 N and then removed.[6 marks](b)A designer proposes that a lifting cable made from this wire should have a safe working load of 450 N, because it does not break until 520 N. Evaluate this proposal.[6 marks]
Total for question 4: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).