Orbital motionEdexcel A-Level Physics: Subtopic test
10 questions, 27 marks
Edexcel A-Level Physics
Orbital motion
Total 27 marks
Name
Class
Date
- 1An Earth-observation satellite moves in a circular orbit at a height of 600 km above the surface of the Earth. The mass of the Earth is 5.97×10²⁴ kg, its radius is 6.37×10⁶ m and the gravitational constant is G = 6.67×10⁻¹¹ N m² kg⁻².(a)Which expression gives the orbital speed v of a satellite in a circular orbit of radius r about a planet of mass M?[1 mark]
- AGM/r
- B√(GM)/r
- C√(GM/r)
- DGM/r²
(b)The satellite is moved into a higher circular orbit. Which row describes the change in its orbital speed and orbital period?[1 mark]- Aspeed decreases, period increases
- Bspeed increases, period increases
- Cspeed increases, period decreases
- Dspeed stays the same, period increases
(c)Calculate the orbital speed of the satellite.[2 marks]Total for question 1: 4 marks
- 2A television company uses a communications satellite that is placed in a geostationary orbit above the Earth. The mass of the Earth is 5.97×10²⁴ kg, its radius is 6.37×10⁶ m and the gravitational constant is G = 6.67×10⁻¹¹ N m² kg⁻². One day is 8.64×10⁴ s.(a)Which row lists conditions that a satellite must satisfy to be in a geostationary orbit?[1 mark]
- AOrbit passes over the poles, period 24 hours
- BOrbit above the equator, period 24 hours, moves in the same direction as the Earth's rotation
- COrbit in any plane, period 12 hours
- DOrbit at a height of about 600 km above the equator
(b)Satellite P orbits the Earth at four times the orbital radius of satellite Q. What is the ratio (period of P) / (period of Q)?[1 mark]- A2
- B4
- C16
- D8
(c)Calculate the orbital radius of the satellite.[2 marks]Total for question 2: 4 marks
- 3The Moon orbits the Earth in an approximately circular path of radius 3.84×10⁸ m. Its orbital period is 27.3 days. Take G = 6.67×10⁻¹¹ N m² kg⁻².(a)Use the motion of the Moon to calculate the mass of the Earth.[3 marks](b)Calculate the orbital speed of the Moon and explain why this speed would be the same if the Moon had twice its mass.[4 marks]
Total for question 3: 7 marks
- 4A navigation satellite is in a circular orbit at a height of 2.02×10⁷ m above the surface of the Earth. The mass of the Earth is 5.97×10²⁴ kg, its radius is 6.37×10⁶ m and the gravitational constant is G = 6.67×10⁻¹¹ N m² kg⁻². A geostationary satellite has an orbital radius of 4.22×10⁷ m.(a)Calculate the orbital period of the navigation satellite and explain why a satellite in a higher circular orbit has a lower speed.[6 marks](b)A student suggests that the navigation satellite could be used as a geostationary satellite. Evaluate this suggestion and describe the conditions for a geostationary orbit.[6 marks]
Total for question 4: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).