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Conservation laws and particle equationsEdexcel A-Level Physics: Subtopic test

10 questions, 27 marks

Edexcel A-Level Physics

Conservation laws and particle equations

Total 27 marks

Name

Class

Date

  1. 1
    In β⁻ decay a neutron in an unstable nucleus changes into a proton, and an electron and a third particle X are emitted. The neutron and proton are baryons with baryon number +1, and the neutron, proton and electron have lepton numbers 0, 0 and +1 respectively.
    (a)
    If the neutron decayed as n → p + e⁻ with no third particle, which quantity would not be conserved?
    [1 mark]
    • ALepton number
    • BCharge
    • CBaryon number
    • DCharge and baryon number
    (b)
    What is particle X?
    [1 mark]
    • AAn electron neutrino
    • BA positron
    • CAn electron antineutrino
    • DA photon
    (c)
    Write the particle equation for the decay and show that charge and lepton number are conserved.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A positive pion (π⁺) decays into a positive muon and a muon neutrino, π⁺ → μ⁺ + νμ. The pion is a meson with baryon number 0 and lepton number 0. Muons and neutrinos are leptons with lepton number +1, and their antiparticles have lepton number −1.
    (a)
    What is the total lepton number of the μ⁺ and the νμ produced?
    [1 mark]
    • A+2
    • B0
    • C−2
    • D+1
    (b)
    Which decay of the π⁺ conserves charge, baryon number and lepton number?
    [1 mark]
    • Aπ⁺ → μ⁺ + ν̄μ
    • Bπ⁺ → μ⁻ + νμ
    • Cπ⁺ → p + ν̄μ
    • Dπ⁺ → e⁺ + νe
    (c)
    The positive muon decays as μ⁺ → e⁺ + νe + ν̄μ. Show that charge and lepton number are conserved in this decay.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Particle physicists analyse the products of high-energy collisions between protons. Pions are mesons with baryon number 0 and lepton number 0; the π⁺, π⁻ and π⁰ have charges +1 e, −1 e and 0. An antiproton has charge −1 e and baryon number −1.
    (a)
    In one collision, p + p → p + n + X, where X is a single particle. Use conservation laws to identify X.
    [3 marks]
    (b)
    A proton and an antiproton collide and annihilate: p + p̄ → π⁺ + π⁻ + π⁰. Show that this is allowed by conservation of charge and baryon number, and explain why the same products cannot be made from two protons.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Nuclei with too many protons become more stable by emitting a positron (β⁺ decay) or by capturing an electron from the atom's inner shell. In each case a proton in the nucleus changes into a neutron and a neutrino is involved.
    (a)
    Explain, with the particle equation, how β⁺ decay conserves charge, baryon number and lepton number, and show how it changes a nucleus such as carbon-11.
    [6 marks]
    (b)
    Determine whether each of these processes is possible, justifying each answer with conservation laws: (i) p → e⁺ + π⁰; (ii) n → p + e⁻; (iii) p + e⁻ → n + νe.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).