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Volume & Surface AreaEdexcel IGCSE Maths: Revision notes

Section 1

How do you find the volume of a prism?

A prism is any 3D solid with a constant cross-section along its length. This includes cuboids, triangular prisms and cylinders.

V=area of cross-section×lengthV = \text{area of cross-section} \times \text{length}

For a cuboid: V=lwhV = lwh

For a cylinder: cross-section is a circle, so V=πr2hV = \pi r^2 h

Always identify the cross-section first, find its area, then multiply by the length/height running perpendicular to it.

Key termsprismcross-section
Exam tip

Sketch the cross-section separately and label it before calculating its area — this stops mix-ups with the wrong dimension.

Common mistake

Do not confuse the 'length' of the prism with a side length of the cross-section — they play different roles in the formula.

Section 2

How do you find the surface area of a prism?

Surface area is the total area of every face on the outside of the solid.

Method:

  1. Identify all the faces (for a cuboid: 3 pairs of rectangles; for a cylinder: 2 circles + 1 curved rectangle).
  2. Find the area of each face.
  3. Add them all together.

For a cuboid: SA=2(lw+lh+wh)SA = 2(lw + lh + wh)

For a cylinder: SA=2πr2+2πrhSA = 2\pi r^2 + 2\pi r h (two circular ends + curved surface, which unrolls into a rectangle of width 2πr2\pi r and height hh).

Key termssurface areanet
Think of it like this

Imagine unfolding the solid flat into its net (like unfolding a cardboard box) — surface area is just the total area of that flat shape.

Example

Cylinder radius 3 cm, height 10 cm: SA=2π(3)2+2π(3)(10)=18π+60π=78π≈245 cm2SA = 2\pi(3)^2 + 2\pi(3)(10) = 18\pi + 60\pi = 78\pi \approx 245\text{ cm}^2.

Section 3

What are the formulae for pyramids and cones?

Pyramids and cones taper to a single apex, so their volume is one third of the equivalent prism/cylinder.

Pyramid volume: V=13×base area×heightV = \dfrac{1}{3} \times \text{base area} \times \text{height}

Cone volume: V=13πr2hV = \dfrac{1}{3}\pi r^2 h

Cone curved surface area: SAcurved=πrlSA_{\text{curved}} = \pi r l, where ll is the slant height (not the vertical height).

Cone total surface area: SA=πrl+πr2SA = \pi r l + \pi r^2

The slant height, radius and vertical height form a right-angled triangle, so l2=r2+h2l^2 = r^2 + h^2 (Pythagoras) when you need to find one from the others.

Key termsslant heightapex
Common mistake

Using the vertical height instead of the slant height in the curved surface area formula is one of the most common exam errors — check which one the question gives you.

Exam tip

If only vertical height and radius are given, use Pythagoras to find slant height before finding surface area.

Section 4

What is the formula for the volume and surface area of a sphere?

A sphere has no flat faces or cross-section, so its formulae must simply be memorised (they are given on the Edexcel formula sheet).

Volume: V=43πr3V = \dfrac{4}{3}\pi r^3

Surface area: SA=4πr2SA = 4\pi r^2

For a hemisphere (half a sphere), halve the sphere volume, but for surface area remember to add the flat circular face: SA=2πr2+πr2=3πr2SA = 2\pi r^2 + \pi r^2 = 3\pi r^2.

Key termshemisphere
Common mistake

Forgetting the flat circular face when finding the total surface area of a hemisphere is a very common lost mark.

Section 5

How do you handle compound and composite solids?

Composite solids are made of two or more basic solids joined together (e.g. a cylinder topped with a hemisphere, or a pyramid on top of a cuboid).

Method:

  1. Split the solid into its basic parts.
  2. Calculate volume/surface area of each part separately.
  3. For volume: add the parts together.
  4. For surface area: add the outer faces only — do NOT include any face that is now hidden inside the joined solid (e.g. the circular face where a hemisphere meets a cylinder is internal and excluded).

Always re-read the question to check whether it wants volume, surface area, or both, and give units cubed (cm3\text{cm}^3) for volume and units squared (cm2\text{cm}^2) for surface area.

Key termscomposite solid
Exam tip

Draw a quick sketch and mark which faces are 'hidden' at the join before adding up surface area.

Example

Cylinder (r = 4, h = 10) with a hemisphere (r = 4) on top: total volume = cylinder volume + hemisphere volume. Total surface area = curved surface of cylinder + one circular base + curved surface of hemisphere (the top circle of the cylinder is hidden, so excluded).

Must Know

  • Volume of any prism = cross-sectional area × length; cylinder: V=πr2hV = \pi r^2 h
  • Cuboid surface area: SA=2(lw+lh+wh)SA = 2(lw + lh + wh); cylinder: SA=2πr2+2πrhSA = 2\pi r^2 + 2\pi r h
  • Pyramid/cone volume is one third of the equivalent prism/cylinder: V=13×base area×hV = \frac{1}{3} \times \text{base area} \times h
  • Cone curved surface area uses slant height ll: SAcurved=πrlSA_{\text{curved}} = \pi r l, with l2=r2+h2l^2 = r^2 + h^2
  • Sphere: V=43πr3V = \frac{4}{3}\pi r^3, SA=4πr2SA = 4\pi r^2 — must be memorised
  • For composite solids, add volumes but exclude hidden internal faces from surface area

That's the notes covered.

Carry on to the next subtopic.