Rate equations, orders and rate constantsAQA A-Level Chemistry: Flashcards
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What is the rate equation for a reaction of A and B?
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- What is the rate equation for a reaction of A and B?
- rate = k[A]ᵐ[B]ⁿ
- Define order of reaction with respect to a reactant.
- The power to which the concentration of that reactant is raised in the rate equation.
- Define rate constant.
- The constant of proportionality in the rate equation; it depends on temperature but not on concentration.
- What are the units of rate?
- mol dm⁻³ s⁻¹
- What is the effect of doubling the concentration of a first-order reactant?
- The rate doubles.
- What is the effect of doubling the concentration of a second-order reactant?
- The rate quadruples.
- What is the effect of changing the concentration of a zero-order reactant?
- None: the reactant does not appear in the rate equation.
- How is the overall order found?
- Add the orders with respect to each reactant.
- What are the units of k for a first-order reaction?
- s⁻¹
- What are the units of k for a second-order reaction?
- dm³ mol⁻¹ s⁻¹
- What are the units of k for a third-order reaction?
- dm⁶ mol⁻² s⁻¹
- How are the orders of reaction found?
- By experiment, for example from initial rate data, not from the balanced equation.
- How does increasing temperature affect k?
- It increases k, so the rate increases at the same concentrations.
Exam questions on Rate equations, orders and rate constants
- A student investigates the reaction between substances A and B at constant temperature. The reaction has the rate equation rate = k[A][B]², where square brackets show concentrations in mol dm⁻³.State what is meant by the statement that the reaction is first order with respect to A.2 marks
- The initial rate of the reaction between substances P and Q was measured at constant temperature in three experiments. Experiment 1: [P] = 0.10 mol dm⁻³, [Q] = 0.10 mol dm⁻³, initial rate = 2.0 × 10⁻⁴ mol dm⁻³ s⁻¹. Experiment 2: [P] = 0.20 mol dm⁻³, [Q] = 0.10 mol dm⁻³, initial rate = 8.0 × 10⁻⁴ mol dm⁻³ s⁻¹. Experiment 3: [P] = 0.20 mol dm⁻³, [Q] = 0.20 mol dm⁻³, initial rate = 1.6 × 10⁻³ mol dm⁻³ s⁻¹.Define the term rate constant, k, and state one factor that changes its value.2 marks
- In acid solution, propanone reacts with iodine: CH₃COCH₃ + I₂ → CH₃COCH₂I + HI. The initial rate was measured in four experiments, with the concentrations of propanone, H⁺ and I₂ in mol dm⁻³. Experiment 1: 1.00, 0.50, 0.0050, rate = 1.35 × 10⁻⁵ mol dm⁻³ s⁻¹. Experiment 2: 2.00, 0.50, 0.0050, rate = 2.70 × 10⁻⁵. Experiment 3: 1.00, 1.00, 0.0050, rate = 2.70 × 10⁻⁵. Experiment 4: 1.00, 0.50, 0.0100, rate = 1.35 × 10⁻⁵.Deduce the order of reaction with respect to each of propanone, H⁺ and I₂. Give your reasoning.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).