Relative masses and the moleAQA A-Level Chemistry: Flashcards
Card 1 of 120 of 12 known
Question
Define relative atomic mass.
Tap or press Space to reveal
Tap card or press Space to flip
See all 12 cards
- Define relative atomic mass.
- The weighted mean mass of an atom of an element compared with 1/12 of the mass of an atom of ¹²C.
- Define relative molecular mass.
- The weighted mean mass of a molecule compared with 1/12 of the mass of an atom of ¹²C.
- When is the term relative formula mass used?
- For ionic compounds, which do not contain molecules.
- What units do relative atomic and relative molecular mass have?
- None, because they are ratios.
- What is the Avogadro constant?
- The number of particles in one mole, 6.02 × 10²³ mol⁻¹.
- What is the relationship between the Avogadro constant and the mole?
- One mole of a substance contains 6.02 × 10²³ particles, so number of particles = amount × 6.02 × 10²³.
- How do you calculate amount in moles from mass?
- Amount = mass (g) ÷ Mr.
- What is the formula for the amount of substance in a solution?
- n = c × V, with V in dm³.
- How do you convert cm³ to dm³?
- Divide by 1000.
- What is the unit of concentration in this course?
- mol dm⁻³.
- How many hydrogen atoms are in 0.100 mol of H₂O?
- 0.200 mol × 6.02 × 10²³ = 1.20 × 10²³ atoms.
- Calculate the Mr of Ca(OH)₂.
- 40.1 + 2 × (16.0 + 1.0) = 74.1
Exam questions on Relative masses and the mole
- Magnesium nitrate, Mg(NO₃)₂, is used in some fireworks as an oxidising agent. A technician needs to convert between masses and amounts of this compound, using relative atomic masses Mg 24.3, N 14.0 and O 16.0.Calculate the amount, in mol, of magnesium nitrate in 7.42 g of Mg(NO₃)₂. Give your answer to 3 significant figures.2 marks
- A student has 3.60 g of water, H₂O, in a beaker. Use relative atomic masses H 1.0 and O 16.0, and the Avogadro constant, 6.02 × 10²³ mol⁻¹.Calculate the mass, in grams, of one molecule of water. Give your answer in standard form to 3 significant figures.2 marks
- A technician prepares a solution of sodium carbonate, Na₂CO₃, by dissolving 6.36 g of the solid in water and making the volume up to exactly 250 cm³ in a volumetric flask. Use relative atomic masses Na 23.0, C 12.0 and O 16.0, and the Avogadro constant, 6.02 × 10²³ mol⁻¹.Calculate the concentration of the sodium carbonate solution in mol dm⁻³.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).