Ligand substitution and the chelate effectAQA A-Level Chemistry: Flashcards
Card 1 of 140 of 14 known
Question
What is ligand substitution?
Tap or press Space to reveal
Tap card or press Space to flip
See all 14 cards
- What is ligand substitution?
- A reaction in which one or more ligands in a complex are replaced by other ligands.
- Why does exchange of NH₃ and H₂O not change the co-ordination number?
- They are similar in size and both are uncharged.
- Give the equation for [Cu(H₂O)₆]²⁺ reacting with excess ammonia.
- [Cu(H₂O)₆]²⁺ + 4NH₃ ⇌ [Cu(NH₃)₄(H₂O)₂]²⁺ + 4H₂O
- What does incomplete substitution mean?
- Only some of the ligands are replaced, as in [Cu(NH₃)₄(H₂O)₂]²⁺.
- Why can exchange of H₂O by Cl⁻ change the co-ordination number?
- Cl⁻ is larger than H₂O and NH₃, so fewer ligands fit around the central ion.
- Give the equation for [Co(H₂O)₆]²⁺ reacting with chloride ions.
- [Co(H₂O)₆]²⁺ + 4Cl⁻ ⇌ [CoCl₄]²⁻ + 6H₂O
- What is a bidentate ligand?
- A ligand that forms two co-ordinate bonds to the central metal ion.
- Name two bidentate ligands.
- Ethane-1,2-diamine, H₂NCH₂CH₂NH₂, and the ethanedioate ion, C₂O₄²⁻.
- What is a multidentate ligand? Give an example.
- A ligand forming more than two co-ordinate bonds; EDTA⁴⁻ forms six.
- What is haem?
- An iron(II) complex with a multidentate ligand, found in haemoglobin.
- How does haemoglobin carry oxygen?
- Oxygen forms a reversible co-ordinate bond to the Fe(II) in haem.
- Why is carbon monoxide toxic?
- It replaces oxygen co-ordinately bonded to Fe(II) in haemoglobin, forming a stronger bond, so oxygen can no longer be carried.
- What is the chelate effect?
- Bidentate and multidentate ligands replace monodentate ligands to form more stable complexes.
- Explain the chelate effect using entropy and enthalpy.
- The number of particles increases, so entropy increases; ΔH is about zero as the same number and type of bonds are made; so ΔG becomes negative.
Exam questions on Ligand substitution and the chelate effect
- Aqueous copper(II) sulfate contains the pale blue complex ion [Cu(H₂O)₆]²⁺. When an excess of concentrated ammonia solution is added the colour changes to deep blue, but the product is [Cu(NH₃)₄(H₂O)₂]²⁺ rather than [Cu(NH₃)₆]²⁺.Explain why the co-ordination number of copper does not change when ammonia replaces water in this reaction.2 marks
- A student investigates reactions of aqueous metal ions with concentrated hydrochloric acid. Aqueous copper(II) sulfate contains [Cu(H₂O)₆]²⁺ and aqueous iron(III) nitrate contains [Fe(H₂O)₆]³⁺. Each reacts with the acid to form a yellow-green solution of [CuCl₄]²⁻ and a yellow solution of [FeCl₄]⁻ respectively.Write an equation for the formation of [CuCl₄]²⁻ from [Cu(H₂O)₆]²⁺ and state the change in co-ordination number of copper.2 marks
- Nickel(II) ions in aqueous solution form [Ni(H₂O)₆]²⁺, and adding excess ammonia solution gives [Ni(NH₃)₆]²⁺. When ethane-1,2-diamine, H₂NCH₂CH₂NH₂ (en), is added, the ammonia ligands are replaced: [Ni(NH₃)₆]²⁺ + 3en → [Ni(en)₃]²⁺ + 6NH₃. This reaction goes essentially to completion at room temperature.Explain why en is described as a bidentate ligand and state the co-ordination number of nickel in [Ni(en)₃]²⁺.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).