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Solution concentrations and titration calculationsEdexcel A-Level Chemistry: Subtopic test

10 questions, 27 marks

Edexcel A-Level Chemistry

Solution concentrations and titration calculations

Total 27 marks

Name

Class

Date

  1. 1
    A school technician prepares sodium hydroxide and hydrochloric acid solutions of known concentration for a titration practical. Use relative atomic masses H = 1.0, O = 16.0, Na = 23.0 and Cl = 35.5.
    (a)
    2.00 g of sodium hydroxide is dissolved in water and made up to 250.0 cm³. What is the concentration of the solution in mol dm⁻³?
    [1 mark]
    • A0.0125 mol dm⁻³
    • B0.0500 mol dm⁻³
    • C0.200 mol dm⁻³
    • D8.00 mol dm⁻³
    (b)
    A solution of hydrochloric acid has a concentration of 0.200 mol dm⁻³. What is its concentration in g dm⁻³?
    [1 mark]
    • A7.30 g dm⁻³
    • B0.00548 g dm⁻³
    • C182.5 g dm⁻³
    • D36.5 g dm⁻³
    (c)
    Calculate the mass of sodium hydroxide needed to make 500 cm³ of a solution of concentration 0.150 mol dm⁻³.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A student titrates 25.0 cm³ portions of sodium hydroxide solution of unknown concentration with 0.100 mol dm⁻³ hydrochloric acid from a burette, repeating the titration until concordant results (within 0.10 cm³ of each other) are obtained. The equation is NaOH + HCl → NaCl + H₂O.
    (a)
    Phenolphthalein is added to the sodium hydroxide in the conical flask. Which colour change shows the end-point as the acid is run in?
    [1 mark]
    • AColourless to pink
    • BYellow to red
    • CRed to yellow
    • DPink to colourless
    (b)
    The titres obtained were 23.10 (rough), 21.80, 21.65, 21.55 and 21.60 cm³. What is the mean titre that should be used in the calculation?
    [1 mark]
    • A21.65 cm³
    • B21.60 cm³
    • C21.94 cm³
    • D23.10 cm³
    (c)
    The mean titre is 21.60 cm³. Calculate the concentration of the sodium hydroxide solution in mol dm⁻³.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A student prepares a standard solution of ethanedioic acid by dissolving 1.575 g of ethanedioic acid dihydrate, H₂C₂O₄·2H₂O (M = 126.0 g mol⁻¹), in water and making the solution up to 250.0 cm³ in a volumetric flask. The student then titrates 25.0 cm³ portions of this solution against sodium hydroxide solution of unknown concentration, using phenolphthalein, and obtains a mean titre of 22.40 cm³. The equation is H₂C₂O₄ + 2NaOH → Na₂C₂O₄ + 2H₂O.
    (a)
    Calculate the concentration of the standard solution of ethanedioic acid in (i) mol dm⁻³ and (ii) g dm⁻³ of the dihydrate.
    [3 marks]
    (b)
    Calculate the concentration of the sodium hydroxide solution in (i) mol dm⁻³ and (ii) g dm⁻³ (M(NaOH) = 40.0 g mol⁻¹).
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    In two core practicals, a class first prepares a standard solution of a solid acid and uses it to find the concentration of a sodium hydroxide solution. The class then uses this sodium hydroxide solution, now of known concentration, to find the concentration of a solution of hydrochloric acid, using phenolphthalein indicator.
    (a)
    Describe how a standard solution of a solid acid should be prepared, explaining why each step is carried out.
    [6 marks]
    (b)
    Describe how the hydrochloric acid solution should be titrated with the sodium hydroxide solution so that the result is accurate and reliable. Include the indicator and its colour change.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).