Half-equations and ionic equationsEdexcel A-Level Chemistry: Subtopic test
10 questions, 27 marks
Edexcel A-Level Chemistry
Half-equations and ionic equations
Total 27 marks
Name
Class
Date
- 1A student places a piece of zinc in blue copper(II) sulfate solution. After some time the blue colour fades and a brown-red solid forms on the zinc.(a)Which equation is the half-equation for the oxidation of zinc?[1 mark]
- AZn²⁺ + 2e⁻ → Zn
- BZn + 2e⁻ → Zn²⁺
- CZn → Zn²⁺ + 2e⁻
- DZn → Zn²⁺ + e⁻
(b)Which half-equation represents the formation of the brown-red solid?[1 mark]- ACu → Cu²⁺ + 2e⁻
- BCu²⁺ → Cu + 2e⁻
- CCu²⁺ + e⁻ → Cu
- DCu²⁺ + 2e⁻ → Cu
(c)Write the ionic equation for the reaction, including state symbols.[2 marks]Total for question 1: 4 marks
- 2Acidified potassium manganate(VII) solution is used to titrate solutions containing iron(II) ions. The purple MnO₄⁻ ion is reduced to the almost colourless Mn²⁺ ion, and Fe²⁺ is oxidised to Fe³⁺.(a)Which is the correct half-equation for the reduction of MnO₄⁻ in acidic solution?[1 mark]
- AMnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O
- BMnO₄⁻ + 4H⁺ + 5e⁻ → Mn²⁺ + 2H₂O
- CMnO₄⁻ + 8H⁺ + 3e⁻ → Mn²⁺ + 4H₂O
- DMnO₄⁻ + 8H⁺ → Mn²⁺ + 4H₂O + 5e⁻
(b)How many moles of Fe²⁺ ions are oxidised by one mole of MnO₄⁻ ions?[1 mark]- A1
- B5
- C4
- D8
(c)Write the overall ionic equation for the reaction between acidified MnO₄⁻ ions and Fe²⁺ ions.[2 marks]Total for question 2: 4 marks
- 3A student studies two redox reactions of iron ions in aqueous solution. In the first, iron(III) ions oxidise iodide ions. In the second, acidified dichromate(VI) ions oxidise iron(II) ions.(a)Write the half-equation for the reduction of Fe³⁺, the half-equation for the oxidation of I⁻ to I₂, and the overall ionic equation.[3 marks](b)Dichromate(VI) ions, Cr₂O₇²⁻, are reduced to Cr³⁺ ions in acid. Construct the half-equation for this change, and combine it with the half-equation Fe²⁺ → Fe³⁺ + e⁻ to give the overall ionic equation.[4 marks]
Total for question 3: 7 marks
- 4A student is practising constructing ionic equations for redox reactions in acidic solution by balancing atoms, charge and electrons.(a)Acidified manganate(VII) ions oxidise hydrogen peroxide to oxygen. The half-equation for manganate(VII) is MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O. Construct the half-equation for the oxidation of H₂O₂ to O₂, combine the two to give the overall ionic equation, and explain which species is the reducing agent.[6 marks](b)Zinc in acid reduces VO₂⁺ ions first to VO²⁺ and then to V³⁺. The half-equations are VO₂⁺ + 2H⁺ + e⁻ → VO²⁺ + H₂O and VO²⁺ + 2H⁺ + e⁻ → V³⁺ + H₂O. Write the half-equation for zinc, construct the overall ionic equation for each of the two steps, and use oxidation numbers to show that vanadium is reduced.[6 marks]
Total for question 4: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).