Colour in transition metal complexesEdexcel A-Level Chemistry: Subtopic test
10 questions, 27 marks
Edexcel A-Level Chemistry
Colour in transition metal complexes
Total 27 marks
Name
Class
Date
- 1A solution containing the complex ion [Ti(H₂O)₆]³⁺ is purple. It absorbs visible light most strongly at a wavelength of 500 nm. Planck constant, h = 6.63 × 10⁻³⁴ J s; speed of light, c = 3.00 × 10⁸ m s⁻¹; Avogadro constant, L = 6.02 × 10²³ mol⁻¹.(a)What is the electron configuration of the Ti³⁺ ion in this complex?[1 mark]
- A[Ar] 4s¹
- B[Ar] 3d¹
- C[Ar] 3d²
- D[Ar] 3d³
(b)What is the energy gap, ΔE, between the d orbitals that corresponds to absorption at 500 nm, in J per ion?[1 mark]- A3.98 × 10⁻²⁸ J
- B1.99 × 10⁻²⁵ J
- C2.40 × 10⁵ J
- D3.98 × 10⁻¹⁹ J
(c)Explain why the solution appears purple.[2 marks]Total for question 1: 4 marks
- 2A student compares the aqueous ions of several d-block elements. The ions are Sc³⁺, Ti³⁺, Fe²⁺, Cu²⁺ and Zn²⁺, each in the form of a hexaaqua complex.(a)Which of these aqueous ions is colourless?[1 mark]
- ASc³⁺
- BTi³⁺
- CFe²⁺
- DCu²⁺
(b)Which statement correctly explains why the aqueous Zn²⁺ ion is colourless?[1 mark]- AIt has no d electrons
- BThe ligands do not split the d orbitals of Zn²⁺
- CIts 3d subshell is full, so no electron can be promoted to a higher d orbital
- DIt absorbs all wavelengths of visible light
(c)Explain why the aqueous Sc³⁺ ion is colourless.[2 marks]Total for question 2: 4 marks
- 3A student adds reagents to a pale blue solution of copper(II) sulfate, which contains [Cu(H₂O)₆]²⁺. Adding an excess of aqueous ammonia gives a deep blue solution containing [Cu(NH₃)₄(H₂O)₂]²⁺. Adding concentrated hydrochloric acid to a fresh sample gives a yellow-green solution containing [CuCl₄]²⁻.(a)Explain why [Cu(NH₃)₄(H₂O)₂]²⁺ is a different colour from [Cu(H₂O)₆]²⁺, even though copper is in the +2 oxidation state in both.[3 marks](b)State the coordination number and shape of [Cu(H₂O)₆]²⁺ and of [CuCl₄]²⁻, and explain why the colour changes when chloride ligands replace water.[4 marks]
Total for question 3: 7 marks
- 4A solution of [Co(H₂O)₆]²⁺ is pink and absorbs light most strongly at a wavelength of 510 nm. Adding concentrated hydrochloric acid turns the solution blue, because [CoCl₄]²⁻ forms. A solution of zinc(II) sulfate under the same conditions is colourless. Planck constant, h = 6.63 × 10⁻³⁴ J s; speed of light, c = 3.00 × 10⁸ m s⁻¹.(a)Explain, in terms of d orbitals, why the solution of [Co(H₂O)₆]²⁺ is coloured and appears pink, and calculate the energy gap ΔE, in J per ion, between the d orbitals involved.[6 marks](b)Explain the colour of [CoCl₄]²⁻ compared with [Co(H₂O)₆]²⁺, and explain why the zinc(II) solution is colourless.[6 marks]
Total for question 4: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).