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Carbon-13 NMREdexcel A-Level Chemistry: Subtopic test

10 questions, 27 marks

Edexcel A-Level Chemistry

Carbon-13 NMR

Total 27 marks

Name

Class

Date

  1. 1
    A technician in a teaching laboratory has two unlabelled bottles of propanol isomers, one containing propan-1-ol and the other propan-2-ol. Both have the molecular formula C₃H₈O. She plans to tell them apart by recording the 13C NMR spectrum of each.
    (a)
    How many peaks are there in the 13C NMR spectrum of propan-1-ol, CH₃CH₂CH₂OH?
    [1 mark]
    • A1
    • B2
    • C3
    • D4
    (b)
    Which carbon atom in propan-1-ol is responsible for the peak at the highest chemical shift?
    [1 mark]
    • AThe carbon of the CH₂ group bonded to the OH group
    • BThe carbon of the CH₃ group
    • CThe carbon of the middle CH₂ group
    • DNone, because all three carbons give a peak at the same shift
    (c)
    Propan-2-ol, CH₃CH(OH)CH₃, gives only two peaks in its 13C NMR spectrum. Explain why.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A pharmaceutical chemist records the 13C NMR spectrum of the solvent ethyl ethanoate, CH₃COOCH₂CH₃. It shows four peaks, at chemical shifts (δ) of 14, 21, 60 and 171 ppm.
    (a)
    How many different carbon environments are there in ethyl ethanoate, CH₃COOCH₂CH₃?
    [1 mark]
    • A1
    • B2
    • C3
    • D4
    (b)
    Which carbon atom gives the peak at δ 60 ppm?
    [1 mark]
    • AThe carbon of the C=O group
    • BThe carbon of the CH₂ group bonded to oxygen
    • CThe carbon of the CH₃ group bonded to the C=O group
    • DThe carbon of the CH₃ group of the ethyl group
    (c)
    Explain why the peak at δ 171 ppm is at a much higher chemical shift than the peak at δ 14 ppm.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A laboratory holds four isomeric alcohols of molecular formula C₄H₁₀O: butan-1-ol, butan-2-ol, 2-methylpropan-1-ol and 2-methylpropan-2-ol. A technician uses 13C NMR spectroscopy to tell them apart. Typical chemical shift ranges (ppm): C–C 5–40; C–O 50–90.
    (a)
    Deduce the number of peaks in the 13C NMR spectra of 2-methylpropan-2-ol and of 2-methylpropan-1-ol, and justify your answers.
    [3 marks]
    (b)
    A sample from the laboratory gives a 13C NMR spectrum with three peaks, at δ 19, 31 and 69 ppm. Deduce which isomer the sample is. Justify your answer and explain the peak at δ 69 ppm.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    An analytical chemist uses 13C NMR spectroscopy to identify isomers in samples from a chemical plant. She counts the peaks in each spectrum and uses these typical chemical shift ranges (ppm): carbon in alkyl groups (C–C) 5–40; ring carbons in benzene derivatives 110–160; C=O in ketones and aldehydes 190–220.
    (a)
    Explain how 13C NMR spectroscopy can be used to distinguish between 1,2-, 1,3- and 1,4-dimethylbenzene.
    [6 marks]
    (b)
    A student claims that compound Z, a ketone of formula C₅H₁₀O, is pentan-2-one. The 13C NMR spectrum of Z has three peaks, at δ 8, 35 and 211 ppm. Evaluate the student's claim and deduce the structure of Z.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).