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Further numerical methodsAQA A-Level Further Maths: Topic test

20 questions, 54 marks

AQA A-Level Further Maths

Further numerical methods topic test

Total 54 marks

Name

Class

Date

  1. 1
    The integral I=∫0211+x2 dxI=\int_0^2\frac{1}{1+x^2}\,dx is to be estimated using Simpson's rule with four strips of equal width.
    (a)
    Which row gives the coefficients of y0, y1, y2, y3, y4y_0,\ y_1,\ y_2,\ y_3,\ y_4, in that order, inside the square bracket of Simpson's rule?
    [1 mark]
    • A1, 2, 2, 2, 11,\ 2,\ 2,\ 2,\ 1
    • B1, 4, 2, 4, 11,\ 4,\ 2,\ 4,\ 1
    • C1, 2, 4, 2, 11,\ 2,\ 4,\ 2,\ 1
    • D4, 1, 2, 1, 44,\ 1,\ 2,\ 1,\ 4
    (b)
    Find the estimate of II given by Simpson's rule, to 4 decimal places.
    [1 mark]
    • A1.10711.1071
    • B1.10381.1038
    • C2.21032.2103
    • D1.10511.1051
    (c)
    The exact value of II is tan⁡−12=1.1071\tan^{-1}2=1.1071 to 4 decimal places. Find the percentage error in the Simpson's rule estimate, to 2 significant figures.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A population PP of bacteria, in thousands, at time tt hours satisfies dPdt=0.2P(1−P50)\frac{dP}{dt}=0.2P\left(1-\frac{P}{50}\right), with P=10P=10 when t=0t=0. Euler's method with step length h=1h=1 is used.
    (a)
    Find the estimate of PP when t=1t=1.
    [1 mark]
    • A11.611.6
    • B1212
    • C1.61.6
    • D11.811.8
    (b)
    Find the estimate of PP when t=2t=2, to 2 decimal places.
    [1 mark]
    • A13.2013.20
    • B13.9213.92
    • C13.3813.38
    • D13.4613.46
    (c)
    Explain why the true value of PP when t=1t=1 is greater than the Euler estimate.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The integral I=∫13ln⁡x dxI=\int_1^3\ln x\,dx is to be estimated using Simpson's rule. The exact value is 3ln⁡3−2=1.29583\ln3-2=1.2958 to 4 decimal places.
    (a)
    Use Simpson's rule with four strips of equal width to estimate II. Give your answer to 4 decimal places.
    [3 marks]
    (b)
    Use Simpson's rule with two strips to estimate II. By comparing the errors, state which of the two Simpson's rule estimates is more accurate and by roughly how much.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A curve satisfies dydx=1x\frac{dy}{dx}=\frac1x with y=0y=0 when x=1x=1. The exact solution is y=ln⁡xy=\ln x, so y(2)=ln⁡2=0.6931y(2)=\ln2=0.6931 to 4 decimal places.
    (a)
    Use Euler's method with step length h=0.25h=0.25 to estimate y(2)y(2), showing the value of yy at each step. Find the percentage error in your estimate, to 2 significant figures.
    [6 marks]
    (b)
    Because dydx\frac{dy}{dx} depends only on xx, y(2)=∫121x dxy(2)=\int_1^2\frac1x\,dx. Use Simpson's rule with four strips to estimate this integral, and by comparing the errors in the two methods explain why Simpson's rule is more accurate than Euler's method here.
    [6 marks]

    Total for question 4: 12 marks

  5. 5
    The integral I=∫14x dxI=\int_1^4\sqrt{x}\,dx is to be estimated using the mid-ordinate rule with three strips of equal width. The exact value is 143\frac{14}{3}.
    (a)
    At which values of xx are the ordinates evaluated?
    [1 mark]
    • A1, 2, 31,\ 2,\ 3
    • B2, 3, 42,\ 3,\ 4
    • C1.5, 2.5, 3.51.5,\ 2.5,\ 3.5
    • D1, 2.5, 41,\ 2.5,\ 4
    (b)
    Find the mid-ordinate estimate of II, to 3 decimal places.
    [1 mark]
    • A4.6774.677
    • B4.6464.646
    • C4.1464.146
    • D5.1465.146
    (c)
    Explain why the estimate is greater than the exact value.
    [2 marks]

    Total for question 5: 4 marks

  6. 6
    A curve satisfies dydx=xy\frac{dy}{dx}=xy with y=2y=2 when x=1x=1. Estimates of yy are found using a step length h=0.1h=0.1. The exact solution is y=2e(x2−1)/2y=2e^{(x^2-1)/2}.
    (a)
    Use Euler's method to estimate yy when x=1.2x=1.2.
    [1 mark]
    • A2.22.2
    • B2.42.4
    • C2.4642.464
    • D2.4422.442
    (b)
    The first step gives y=2.2y=2.2 when x=1.1x=1.1. Use the improved Euler method yr+1=yr−1+2hf(xr,yr)y_{r+1}=y_{r-1}+2hf(x_r,y_r) to estimate yy when x=1.2x=1.2.
    [1 mark]
    • A2.4422.442
    • B2.4842.484
    • C2.422.42
    • D2.6842.684
    (c)
    Use the exact solution to find the error in each of the estimates of y(1.2)y(1.2) found in parts (a) and (b), and state which method is more accurate.
    [2 marks]

    Total for question 6: 4 marks

  7. 7
    The speed vv of a train, in m s⁻¹, is measured every 1010 seconds as it leaves a station. The readings at t=0, 10, 20, …, 60t=0,\ 10,\ 20,\ \ldots,\ 60 seconds are 0, 4.2, 9.1, 12.6, 14.0, 14.80,\ 4.2,\ 9.1,\ 12.6,\ 14.0,\ 14.8 and 15.015.0.
    (a)
    Use Simpson's rule to estimate the distance travelled by the train in the first 60 seconds.
    [3 marks]
    (b)
    Use the mid-ordinate rule with three strips of width 2020 s, using the readings at t=10, 30t=10,\ 30 and 5050, to find a second estimate of the distance. Find the difference between the two estimates as a percentage of the Simpson's rule estimate, to 2 significant figures.
    [4 marks]

    Total for question 7: 7 marks

  8. 8
    A curve satisfies dydx=sin⁡x\frac{dy}{dx}=\sin x with y=0y=0 when x=0x=0, where xx is in radians. The exact solution is y=1−cos⁡xy=1-\cos x, so y(π2)=1y\left(\frac{\pi}{2}\right)=1.
    (a)
    Use Euler's method with step length h=π4h=\frac{\pi}{4} to estimate y(π4)y\left(\frac{\pi}{4}\right). Then use the improved Euler method yr+1=yr−1+2hf(xr,yr)y_{r+1}=y_{r-1}+2hf(x_r,y_r) to estimate y(π2)y\left(\frac{\pi}{2}\right), and find the percentage error in this estimate, to 3 significant figures.
    [6 marks]
    (b)
    Use Simpson's rule with two strips to estimate ∫0π/2sin⁡x dx\int_0^{\pi/2}\sin x\,dx, which equals y(π2)y\left(\frac{\pi}{2}\right), and find the percentage error. Show that the improved Euler estimate in part (a) is equal to the mid-ordinate rule estimate with one strip.
    [6 marks]

    Total for question 8: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).