Simple harmonic motionEdexcel International A Level Physics: Subtopic test
10 questions, 27 marks
Edexcel International A Level Physics
Simple harmonic motion
Total 27 marks
Name
Class
Date
- 1A trolley of mass 0.40 kg rests on a horizontal, frictionless track. It is attached to a fixed support by a spring that obeys Hooke's law, with spring constant 25 N m⁻¹. The trolley is pulled 6.0 cm from its equilibrium position and released.(a)Which statement gives the condition for simple harmonic motion?[1 mark]
- AThe resultant force is constant in magnitude and always directed towards the equilibrium position
- BThe resultant force is proportional to the displacement and directed away from the equilibrium position
- CThe resultant force is proportional to the displacement from the equilibrium position and directed towards it
- DThe resultant force is proportional to the square of the displacement and directed towards the equilibrium position
(b)Which of the following would also be expected to show simple harmonic motion?[1 mark]- AA mass on a spring, oscillating with a small amplitude within the limit of proportionality
- BA ball bouncing repeatedly on a hard floor
- CA car moving at constant speed around a circular track
- DA pendulum swung through an angle of 120°
(c)Explain why the trolley moves with simple harmonic motion after it is released.[2 marks]Total for question 1: 4 marks
- 2A particle oscillates with simple harmonic motion with an amplitude of 4.0 cm and a frequency of 2.5 Hz. At time t = 0 it is at its maximum positive displacement.(a)What is the angular frequency of the oscillation?[1 mark]
- A0.40 rad s⁻¹
- B15.7 rad s⁻¹
- C7.9 rad s⁻¹
- D2.5 rad s⁻¹
(b)Which equation gives the displacement x, in metres, at time t, in seconds?[1 mark]- Ax = 0.040 sin 15.7t
- Bx = 0.040 cos 2.5t
- Cx = 15.7 cos 0.040t
- Dx = 0.040 cos 15.7t
(c)Calculate the maximum speed and the maximum magnitude of the acceleration of the particle.[2 marks]Total for question 2: 4 marks
- 3A student compares the oscillations of a mass on a spring with those of a simple pendulum. The mass-spring system consists of a mass of 0.250 kg suspended from a spring of spring constant 40 N m⁻¹. Use g = 9.81 m s⁻².(a)Calculate the period and the frequency of oscillation of the mass-spring system.[3 marks](b)The student wants a simple pendulum with the same period as this mass-spring system. Calculate the length of the pendulum. Then explain why quadrupling the mass on the spring doubles its period, whereas the period of a pendulum does not depend on the mass of the bob.[4 marks]
Total for question 3: 7 marks
- 4An oceanography team studies a buoy that bobs vertically in the sea with simple harmonic motion, with an amplitude of 0.60 m and a period of 5.0 s. At t = 0 the buoy is at the top of its motion. The team also tests the same ideas using a mass on a spring and a simple pendulum in the laboratory.(a)Calculate the displacement, velocity and acceleration of the buoy 1.0 s after the top of its motion. Take upward as positive.[6 marks](b)Starting from F = −kx, show that the period of a mass-spring oscillator is T = 2π√(m/k), and explain why a simple pendulum behaves as a simple harmonic oscillator only for small angles.[6 marks]
Total for question 4: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).