Stationary wavesEdexcel International A Level Physics: Subtopic test
10 questions, 27 marks
Edexcel International A Level Physics
Stationary waves
Total 27 marks
Name
Class
Date
- 1A student fixes one end of a long elastic cord to a wall and shakes the other end up and down. At one particular frequency a stationary wave appears on the cord, with the cord appearing still at certain points and vibrating with large amplitude at others.(a)Which statement correctly describes a node on a stationary wave?[1 mark]
- AA point where the amplitude of vibration is a maximum
- BA point where the amplitude of vibration is always zero
- CA point that is momentarily at rest once in each cycle
- DA point where the wave transfers the greatest amount of energy
(b)Two adjacent nodes on the cord are 0.15 m apart. What is the wavelength of the waves that form the stationary wave?[1 mark]- A0.075 m
- B0.15 m
- C0.30 m
- D0.60 m
(c)Explain how the stationary wave is formed on the cord.[2 marks]Total for question 1: 4 marks
- 2A guitar string of length 0.60 m and mass per unit length 4.0 × 10⁻⁴ kg m⁻¹ is fixed at both ends. It is held under a tension of 36 N and plucked so that it vibrates in its fundamental mode (one antinode).(a)Calculate the speed of transverse waves on the string.[1 mark]
- A300 m s⁻¹
- B150 m s⁻¹
- C600 m s⁻¹
- D9.0 × 10⁴ m s⁻¹
(b)What is the frequency of the fundamental mode of this string?[1 mark]- A125 Hz
- B500 Hz
- C750 Hz
- D250 Hz
(c)The guitarist tightens the string until the tension is 64 N. Calculate the new frequency of the fundamental mode.[2 marks]Total for question 2: 4 marks
- 3In Core Practical 5 a student investigates a string of length 0.80 m and mass per unit length 1.5 × 10⁻³ kg m⁻¹. One end is attached to a vibration generator connected to a signal generator. The string passes over a pulley, and a hanging mass at the other end provides the tension. The student takes g = 9.81 N kg⁻¹.(a)Describe how the student can find the frequency of the fundamental stationary wave on the string.[3 marks](b)The hanging mass is 0.50 kg. Calculate the frequency of the fundamental. State and explain the effect on this frequency of increasing the hanging mass to 2.0 kg.[4 marks]
Total for question 3: 7 marks
- 4A stringed-instrument maker is choosing strings for a small harp. Each string is 0.65 m long and fixed at both ends, and is tuned by adjusting its tension. String A has a mass per unit length of 5.0 × 10⁻⁴ kg m⁻¹ and is under a tension of 80 N. String B has a mass per unit length of 2.0 × 10⁻³ kg m⁻¹ and is also under a tension of 80 N.(a)Explain how a stationary wave forms on a string fixed at both ends, and why a string can only vibrate in a stationary wave pattern at certain frequencies. Refer to nodes and antinodes in your answer.[6 marks](b)Calculate the fundamental frequency of each string. Explain why the two frequencies differ, and calculate the tension needed to make string B give the same fundamental frequency as string A.[6 marks]
Total for question 4: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).