Orbital motionEdexcel International A Level Physics: Subtopic test
10 questions, 27 marks
Edexcel International A Level Physics
Orbital motion
Total 27 marks
Name
Class
Date
- 1The International Space Station (ISS) moves in a circular orbit at a height of 4.0 × 10⁵ m above the Earth's surface. The Earth has mass 5.97 × 10²⁴ kg and radius 6.37 × 10⁶ m. G = 6.67 × 10⁻¹¹ N m² kg⁻².(a)What provides the centripetal force that keeps the ISS in orbit?[1 mark]
- AThrust from the station's engines
- BA centrifugal force acting outwards
- CThe gravitational attraction between the Earth and the station
- DAir resistance acting on the station
(b)What is the orbital speed of the ISS?[1 mark]- A5.9 × 10⁷ m s⁻¹
- B3.2 × 10⁴ m s⁻¹
- C7.91 × 10³ m s⁻¹
- D7.67 × 10³ m s⁻¹
(c)Calculate the time taken for the ISS to complete one orbit.[2 marks]Total for question 1: 4 marks
- 2A geostationary communications satellite remains above the same point on the Earth's surface. The Earth has mass 5.97 × 10²⁴ kg and radius 6.37 × 10⁶ m, and it rotates once in 8.62 × 10⁴ s (one sidereal day). G = 6.67 × 10⁻¹¹ N m² kg⁻².(a)Which statement must be true for the satellite to be geostationary?[1 mark]
- AIt orbits in a plane that passes through the poles
- BIt orbits in the plane of the equator, in the same direction as the Earth's rotation
- CIt orbits just above the Earth's atmosphere
- DIts acceleration is zero
(b)What is the radius of the orbit of the satellite, measured from the centre of the Earth?[1 mark]- A4.21 × 10⁷ m
- B3.58 × 10⁷ m
- C7.49 × 10²² m
- D1.8 × 10⁵ m
(c)Explain why a geostationary satellite must orbit in the plane of the equator.[2 marks]Total for question 2: 4 marks
- 3Mars moves in an approximately circular orbit of radius 2.28 × 10¹¹ m around the Sun, which has mass 1.99 × 10³⁰ kg. G = 6.67 × 10⁻¹¹ N m² kg⁻². Take one year to be 3.16 × 10⁷ s.(a)Show that the orbital period T of a planet in a circular orbit of radius r around the Sun is given by T² = 4π²r³/GM, where M is the mass of the Sun.[3 marks](b)Calculate the orbital period of Mars in years.[4 marks]
Total for question 3: 7 marks
- 4Satellites in the Global Positioning System (GPS) move in circular orbits of radius 2.66 × 10⁷ m around the Earth, which has mass 5.97 × 10²⁴ kg. G = 6.67 × 10⁻¹¹ N m² kg⁻². The Earth rotates once in 8.62 × 10⁴ s.(a)Explain, using Newton's laws of motion and the law of gravitation, why the orbital speed of a satellite depends on the radius of its orbit but not on its mass, and why a satellite in a higher orbit has a longer period.[6 marks](b)Calculate the orbital speed and the period of a GPS satellite, and hence deduce how many orbits it completes in one rotation of the Earth.[6 marks]
Total for question 4: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).