Resistance changes in thermistors and LDRsEdexcel International A Level Physics: Subtopic test
10 questions, 27 marks
Edexcel International A Level Physics
Resistance changes in thermistors and LDRs
Total 27 marks
Name
Class
Date
- 1A technician heats a metal wire and a negative temperature coefficient (NTC) thermistor, one at a time, from 20 °C to 80 °C. Each is connected to a constant 5.0 V supply of negligible internal resistance through an ammeter.(a)Why does the resistance of the metal wire increase as it is heated?[1 mark]
- AThe number of conduction electrons increases
- BThe wire contracts and becomes thinner
- CThe lattice ions vibrate with larger amplitude, so conduction electrons collide with them more often
- DThe conduction electrons are released from their atoms more easily
(b)What happens to the current in the thermistor as it is heated, and why?[1 mark]- AIt increases, because more electrons are released and the number of conduction electrons rises
- BIt decreases, because the lattice ions vibrate more
- CIt stays the same, because the potential difference is constant
- DIt increases, because the lattice ions vibrate less
(c)The thermistor current is 2.0 mA at 20 °C and 12.5 mA at 80 °C. Calculate the resistance of the thermistor at each temperature.[2 marks]Total for question 1: 4 marks
- 2A light-dependent resistor (LDR) is connected to a 6.0 V supply of negligible internal resistance through an ammeter. The ammeter reads 12 mA in bright light and 0.10 mA in darkness.(a)Calculate the resistance of the LDR in bright light.[1 mark]
- A2.0 Ω
- B500 Ω
- C72 Ω
- D0.50 Ω
(b)What is the best explanation for the fall in resistance of the LDR in bright light?[1 mark]- AThe lattice ions vibrate more, so the resistance falls
- BThe LDR is warmed by the light, so its length decreases
- CLight makes the conduction electrons move faster
- DPhotons release electrons from atoms, increasing the number of conduction electrons
(c)Calculate the resistance of the LDR in darkness and how many times larger it is than in bright light.[2 marks]Total for question 2: 4 marks
- 3A thermistor is connected across a 5.0 V supply of negligible internal resistance. Its resistance is 2.0 kΩ at 25 °C and 0.30 kΩ at 75 °C.(a)Calculate the current in the thermistor at each temperature and the percentage increase in the current between 25 °C and 75 °C.[3 marks](b)Explain, using a model of conduction, why heating a metal conductor increases its resistance whereas heating this thermistor decreases its resistance.[4 marks]
Total for question 3: 7 marks
- 4A greenhouse controller uses a light-dependent resistor (LDR) to sense daylight and a negative temperature coefficient (NTC) thermistor to sense the temperature.(a)Explain how the resistance of the LDR changes with illumination, in terms of the conduction electrons in the LDR.[6 marks](b)The designer is deciding whether the thermistor or a platinum wire coil is the better temperature sensor between 0 °C and 100 °C. The coil has a resistance of 100 Ω at 0 °C and 139 Ω at 100 °C. The thermistor has a resistance of 8.0 kΩ at 0 °C and 0.50 kΩ at 100 °C. Evaluate which should be chosen.[6 marks]
Total for question 4: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).