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2.12 Polynomial functionsIB Maths: Analysis and Approaches HL: Revision notes

Section 1

Polynomials, zeros and graphs

A polynomial of degree nn is p(x)=anxn+an−1xn−1+⋯+a1x+a0p(x) = a_{n}x^{n} + a_{n-1}x^{n-1} + \cdots + a_{1}x + a_{0} with an≠0a_{n} \ne 0. Its zeros are the values of xx with p(x)=0p(x) = 0; they are the roots of p(x)=0p(x) = 0 and the xx-intercepts of y=p(x)y = p(x).

  • A degree nn polynomial has at most nn real zeros and at most n−1n - 1 turning points.
  • The end behaviour follows the leading term anxna_{n}x^{n}: for a cubic with a3>0a_{3} > 0, y→∞y \to \infty as x→∞x \to \infty and y→−∞y \to -\infty as x→−∞x \to -\infty.
  • A single zero: the graph crosses the axis. A repeated (double) zero, from a factor (x−r)2(x - r)^{2}: the graph touches the axis there. A triple zero: the graph crosses with a point of inflection.
  • The yy-intercept is a0a_{0}.
Key termszerorepeated rootend behaviour
Exam tip

To build a polynomial from its zeros, write a(x−r1)(x−r2)⋯a(x - r_1)(x - r_2)\cdots and use one more point (often the yy-intercept) to find aa.

Section 2

The factor and remainder theorems

Remainder theorem: when p(x)p(x) is divided by (x−a)(x - a), the remainder is p(a)p(a). When divided by (ax−b)(ax - b) the remainder is p(ba)p\left(\frac{b}{a}\right).

Factor theorem: (x−a)(x - a) is a factor of p(x)p(x) if and only if p(a)=0p(a) = 0.

Example: p(x)=2x3+ax2+bx−6p(x) = 2x^{3} + ax^{2} + bx - 6 with factor (x−2)(x - 2) and remainder −6-6 on division by (x+1)(x + 1) gives 4a+2b=−104a + 2b = -10 and a−b=2a - b = 2, so a=−1a = -1, b=−3b = -3.

Key termsremainder theoremfactor theorem
Common mistake

Dividing by (x+1)(x + 1) means substituting x=−1x = -1, not x=1x = 1.

Section 3

Factorising a cubic

  1. Find one root by trying factors of a0an\frac{a_{0}}{a_{n}} (e.g. h(3)=0h(3) = 0).
  2. Divide by (x−r)(x - r) — long division, synthetic division or comparing coefficients — to get a quadratic.
  3. Factorise or solve the quadratic; if its discriminant is negative there are no more real roots.

x3+7x2+10x−120=(x−3)(x2+10x+40)x^{3} + 7x^{2} + 10x - 120 = (x - 3)(x^{2} + 10x + 40), and Δ=−60<0\Delta = -60 < 0, so x=3x = 3 is the only real root.

Key termscomparing coefficients

Section 4

Sum and product of the roots

For anxn+an−1xn−1+⋯+a0=0a_{n}x^{n} + a_{n-1}x^{n-1} + \cdots + a_{0} = 0 (formula booklet):

sum of roots=−an−1an,product of roots=(−1)na0an.\text{sum of roots} = -\frac{a_{n-1}}{a_{n}}, \qquad \text{product of roots} = \frac{(-1)^{n}a_{0}}{a_{n}}.

For 3x4−6x3+kx2+5x−12=03x^{4} - 6x^{3} + kx^{2} + 5x - 12 = 0: sum =2= 2, product =−4= -4, whatever the value of kk.

These results count complex roots and repeated roots too. They let you find sums and products without solving, e.g. the volume (αβγ\alpha\beta\gamma) of a box whose edges are the roots of a cubic. If each root is multiplied by 2, the sum doubles and the product is multiplied by 2n2^{n}.

Key termssum of rootsproduct of roots
Common mistake

Forgetting (−1)n(-1)^{n}: for a cubic the product is −a0a3-\frac{a_{0}}{a_{3}}, for a quartic it is +a0a4+\frac{a_{0}}{a_{4}}.

Exam tip

Divide by the leading coefficient first if it is not 1 — the most common lost mark.

Must know

  • Zeros ⇔ roots ⇔ factors ⇔ xx-intercepts; repeated roots touch the axis.
  • Remainder on dividing by (x−a)(x - a) is p(a)p(a); (x−a)(x - a) is a factor iff p(a)=0p(a) = 0.
  • Factorise a cubic: find a root, divide, deal with the quadratic.
  • Sum =−an−1an= -\frac{a_{n-1}}{a_{n}}, product =(−1)na0an= \frac{(-1)^{n}a_{0}}{a_{n}}.

That's the notes covered.

Carry on to the next subtopic.