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5.1 Limits and the derivativeIB Maths: Analysis and Approaches HL: Subtopic test

10 questions, 27 marks

IB Maths: Analysis and Approaches HL

5.1 Limits and the derivative

Total 27 marks

Name

Class

Date

  1. 1
    The function ff is defined by f(x)=x2−2xf(x)=x^{2}-2x. The point PP on the curve y=f(x)y=f(x) has xx-coordinate 3, and the point QQ on the same curve has xx-coordinate 3+h3+h, where h≠0h\neq0.
    (a)
    Find the gradient of the chord PQPQ when h=0.1h=0.1.
    [1 mark]
    • A0.410.41
    • B44
    • C4.014.01
    • D4.14.1
    (b)
    The gradient of the chord PQPQ is calculated for values of hh that get closer and closer to 0. Write down the value that these chord gradients approach.
    [1 mark]
    • A33
    • B00
    • C44
    • D66
    (c)
    Show that the gradient of the chord PQPQ is 4+h4+h.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A cup of coffee is left to cool. Its temperature, TT °C, tt minutes after it is poured, is recorded. The coffee is at 90 °C when t=0t=0 and at 62.5 °C when t=10t=10. The average rate of change of TT is calculated over short time intervals that start or end at t=10t=10. From t=10t=10 to t=10+ht=10+h, the average rate of change is −2.0707-2.0707 °C per minute when h=1h=1, −2.1176-2.1176 when h=0.1h=0.1 and −2.1223-2.1223 when h=0.01h=0.01. From t=10−ht=10-h to t=10t=10, it is −2.1768-2.1768 when h=1h=1, −2.1282-2.1282 when h=0.1h=0.1 and −2.1234-2.1234 when h=0.01h=0.01.
    (a)
    Estimate the instantaneous rate of change of the temperature of the coffee when t=10t=10, giving your answer to three significant figures.
    [1 mark]
    • A−2.07-2.07
    • B−2.12-2.12
    • C−2.18-2.18
    • D2.122.12
    (b)
    Which statement correctly interprets the value of dTdt\frac{\mathrm{d}T}{\mathrm{d}t} at t=10t=10?
    [1 mark]
    • AAt t=10t=10 the temperature is falling at about 2.12 °C per minute.
    • BAt t=10t=10 the temperature of the coffee is about 2.12 °C.
    • CIn the first 10 minutes the temperature falls by about 2.12 °C.
    • DIt takes about 2.12 minutes for the temperature to fall by 1 °C.
    (c)
    Find the average rate of change of the temperature of the coffee between t=0t=0 and t=10t=10. Give your answer with units.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The curve CC has equation y=x3y=x^{3}. The point A(2, 8)A(2,\,8) lies on CC, and the point BB on CC has xx-coordinate 2+h2+h, where h>0h>0.
    (a)
    Show that the gradient of the chord ABAB is 12+6h+h212+6h+h^{2}.
    [3 marks]
    (b)
    Hence write down the gradient of CC at AA, and find the set of values of hh for which the gradient of the chord ABAB differs from the gradient of CC at AA by less than 0.61.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A stone is dropped from rest from the top of a sea cliff that is 78.4 m high. The distance, ss metres, that the stone has fallen tt seconds after it is released is modelled by s=4.9t2s=4.9t^{2}, until the stone reaches the sea.
    (a)
    (i) Find the average speed of the stone during the first 2 seconds of its fall.
    (ii) Show that the average speed of the stone between
    t=2t=2 and t=2+ht=2+h is 19.6+4.9h19.6+4.9h m s−1^{-1}, where h>0h>0.
    (iii) Hence deduce the speed of the stone when
    t=2t=2.
    [6 marks]
    (b)
    (i) Find the time taken for the stone to reach the sea.
    (ii) By considering the average speed between times
    tt and t+ht+h, show that dsdt=9.8t\frac{\mathrm{d}s}{\mathrm{d}t}=9.8t.
    (iii) Hence find the speed of the stone as it reaches the sea.
    [6 marks]

    Total for question 4: 12 marks

End of questions